a: 50.0, b: 11.2, c: 4.46, d: ≥0.05, e: 29.0a: 50.0, b: 11.2, c: 4.46, d: ≤0.05, e: 29.0a: 11.2, b: 50.0, c: ≤0.05, d: 4.46, e: 29.0a: 4.46, b: 11.2, c: 29.0, d: 0.05, e: 50.0a: 29.0, b: 4.46, c: 11.2, d: ≤0.05, e: 50.0a: 50.0, b: 11.2, c: ≥0.05, d: 29.0, e: 4.46 The following table shows the results of an anova comparing the means of yield frompumpkin patches planted under different treatments of artificial fertilizer application.One group was a control, while others were planted in soils where nitrogen orphosphorus had been applied. Given the null f-distribution in the figure below, whichhas the critical value at alpha = 0.05 indicated by the vertical line, match the values tothe letters in the ANOVA table.probability density1.00.80.60.0 0.2 0.4TreatmentErrorDegreesoffreedom227e2Sum MeanSquares Squares100.0302.44abF distribution6F-valueC8P-valued10

Given that, No. of treatments (k) = 3Level of significance (α)=0.05 The partial ANOVA output is…

Answered: The following table shows the results…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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