### Virtual Memory System Core MapThe following table provides the core map (which contains more information than a page table) of a virtual memory system at time \( t \), which features a page size of 1000 bytes.#### Core Map Table| Process ID | Page # | Frame # ||------------|--------|---------|| 1 | 1 | 0 || 1 | 2 | 1 || 2 | 2 | 2 || 3 | 1 | 3 || 1 | 3 | 4 || 2 | 1 | 5 || 2 | 0 | 6 || 3 | 2 | 7 |#### Question:To which physical address does virtual address 1300 of process 1 map? [If the page is not in the main memory, please choose 'does not map']#### Options:- a. 2300- b. 300- c. does not map- d. 1300- e. 3300### Solution Process1. **Calculate the Virtual Page Number and Offset:** - Virtual address 1300 in process 1: - Page size = 1000 bytes - Virtual Page Number (VPN) = ⌊1300 / 1000⌋ = 1 - Offset within the page = 1300 % 1000 = 3002. **Map VPN to Physical Frame:** - From the table, for process 1 and page number 1, the frame number is 0.3. **Calculate Physical Address:** - Physical Address = (Frame Number * Page Size) + Offset - Physical Address = (0 * 1000) + 300 = 300### Answer:- The correct physical address is **300** (Option b).

SOLUTION -The correct answer is " (d) 1300 "Given, Page size = 1000 bytesNo for Process 1It consists…

The following table shows the core map (having more information than page table) of a virtual memory system at time t, which has a page size of 1000 bytes. Process ID Page # 1 1 2 3~ ~ 3 2 2 1 2 2 1 3 1 10 2 Frame # 10 1 2 3 4 5 6 17 To which physical address does virtual address 1300 of process 1 map? [If the page is not in the main memory, please choose 'does not map']

The following table shows the core map (having more information than page table) of a virtual memory system at time t, which has a page size of 1000 bytes. Process ID Page # 1 1 2 3~ ~ 3 2 2 1 2 2 1 3 1 10 2 Frame # 10 1 2 3 4 5 6 17 To which physical address does virtual address 1300 of process 1 map? [If the page is not in the main memory, please choose 'does not map']

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Types of database architectures

A Database Architecture represents the Database Management System’s (DBMS) design (schema). The DBMS architecture makes it easy to understand the components involved in the database system and their relations. The DBMS architecture may vary based on the system on which it runs. Some systems contain both client and server machines whereas some run only on a server machine. Based on the architecture, the system can be classified as centralized, decentralized, or hierarchical.

Question

### Virtual Memory System Core Map

The following table provides the core map (which contains more information than a page table) of a virtual memory system at time \( t \), which features a page size of 1000 bytes.

#### Core Map Table

| Process ID | Page # | Frame # |
|------------|--------|---------|
| 1 | 1 | 0 |
| 1 | 2 | 1 |
| 2 | 2 | 2 |
| 3 | 1 | 3 |
| 1 | 3 | 4 |
| 2 | 1 | 5 |
| 2 | 0 | 6 |
| 3 | 2 | 7 |

#### Question:
To which physical address does virtual address 1300 of process 1 map?

[If the page is not in the main memory, please choose 'does not map']

#### Options:

- a. 2300
- b. 300
- c. does not map
- d. 1300
- e. 3300

### Solution Process

1. **Calculate the Virtual Page Number and Offset:**
- Virtual address 1300 in process 1:
- Page size = 1000 bytes
- Virtual Page Number (VPN) = ⌊1300 / 1000⌋ = 1
- Offset within the page = 1300 % 1000 = 300

2. **Map VPN to Physical Frame:**
- From the table, for process 1 and page number 1, the frame number is 0.

3. **Calculate Physical Address:**
- Physical Address = (Frame Number * Page Size) + Offset
- Physical Address = (0 * 1000) + 300 = 300

### Answer:
- The correct physical address is **300** (Option b).

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