The following table shows the core map (having more information than page table) of a virtual memory system at time t, which has a page size of 1000 bytes. Process ID Page # 1 1 2 3~ ~ 3 2 2 1 2 2 1 3 1 10 2 Frame # 10 1 2 3 4 5 6 17 To which physical address does virtual address 1300 of process 1 map? [If the page is not in the main memory, please choose 'does not map']
The following table shows the core map (having more information than page table) of a virtual memory system at time t, which has a page size of 1000 bytes. Process ID Page # 1 1 2 3~ ~ 3 2 2 1 2 2 1 3 1 10 2 Frame # 10 1 2 3 4 5 6 17 To which physical address does virtual address 1300 of process 1 map? [If the page is not in the main memory, please choose 'does not map']
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![### Virtual Memory System Core Map
The following table provides the core map (which contains more information than a page table) of a virtual memory system at time \( t \), which features a page size of 1000 bytes.
#### Core Map Table
| Process ID | Page # | Frame # |
|------------|--------|---------|
| 1 | 1 | 0 |
| 1 | 2 | 1 |
| 2 | 2 | 2 |
| 3 | 1 | 3 |
| 1 | 3 | 4 |
| 2 | 1 | 5 |
| 2 | 0 | 6 |
| 3 | 2 | 7 |
#### Question:
To which physical address does virtual address 1300 of process 1 map?
[If the page is not in the main memory, please choose 'does not map']
#### Options:
- a. 2300
- b. 300
- c. does not map
- d. 1300
- e. 3300
### Solution Process
1. **Calculate the Virtual Page Number and Offset:**
- Virtual address 1300 in process 1:
- Page size = 1000 bytes
- Virtual Page Number (VPN) = ⌊1300 / 1000⌋ = 1
- Offset within the page = 1300 % 1000 = 300
2. **Map VPN to Physical Frame:**
- From the table, for process 1 and page number 1, the frame number is 0.
3. **Calculate Physical Address:**
- Physical Address = (Frame Number * Page Size) + Offset
- Physical Address = (0 * 1000) + 300 = 300
### Answer:
- The correct physical address is **300** (Option b).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F20321579-9a21-4ca5-a504-733b11c2456d%2F74a49ed7-34f8-4a25-9ef1-81f2e2423192%2F63jdej_processed.png&w=3840&q=75)
Transcribed Image Text:### Virtual Memory System Core Map
The following table provides the core map (which contains more information than a page table) of a virtual memory system at time \( t \), which features a page size of 1000 bytes.
#### Core Map Table
| Process ID | Page # | Frame # |
|------------|--------|---------|
| 1 | 1 | 0 |
| 1 | 2 | 1 |
| 2 | 2 | 2 |
| 3 | 1 | 3 |
| 1 | 3 | 4 |
| 2 | 1 | 5 |
| 2 | 0 | 6 |
| 3 | 2 | 7 |
#### Question:
To which physical address does virtual address 1300 of process 1 map?
[If the page is not in the main memory, please choose 'does not map']
#### Options:
- a. 2300
- b. 300
- c. does not map
- d. 1300
- e. 3300
### Solution Process
1. **Calculate the Virtual Page Number and Offset:**
- Virtual address 1300 in process 1:
- Page size = 1000 bytes
- Virtual Page Number (VPN) = ⌊1300 / 1000⌋ = 1
- Offset within the page = 1300 % 1000 = 300
2. **Map VPN to Physical Frame:**
- From the table, for process 1 and page number 1, the frame number is 0.
3. **Calculate Physical Address:**
- Physical Address = (Frame Number * Page Size) + Offset
- Physical Address = (0 * 1000) + 300 = 300
### Answer:
- The correct physical address is **300** (Option b).
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