Consider an operating system that uses 48-bit virtual addresses and 16KB pages. The system uses a multi-level page table design to store all the page table entries of a process, and each page table entry and index entry are 4 bytes in size. What is the total number of page that are required to store the page table entries of a process, across all levels of the page table? You may follow the hint below or finish from scratch to fill the blanks. Please show your calculations to get partial points like 2^10/2^4=2^6. 1. We need to calculate the total number of page table entries needed for a process (i.e., the total number of pages for a process) 2. We need to calculate how many entries each page can store 3. With 1 and 2, we can calculate how many pages needed for the lowest (innermost) level 4. Each page from 3 requires an entry (pointer) in the upper (next) level. We need to calculate how many pages are required to store this next level entries (please note the entry size is always 4 bytes, i.e., the number of entries that can be stored in each page is always the number from 2) 5. So on and so forth until one directory page can hold all entries pointing to its inner level. Now, we can calculate the total number of pages required to store all page table entries
Consider an operating system that uses 48-bit virtual addresses and 16KB pages. The system uses a multi-level page table design to store all the page table entries of a process, and each page table entry and index entry are 4 bytes in size. What is the total number of page that are required to store the page table entries of a process, across all levels of the page table? You may follow the hint below or finish from scratch to fill the blanks. Please show your calculations to get partial points like 2^10/2^4=2^6. 1. We need to calculate the total number of page table entries needed for a process (i.e., the total number of pages for a process) 2. We need to calculate how many entries each page can store 3. With 1 and 2, we can calculate how many pages needed for the lowest (innermost) level 4. Each page from 3 requires an entry (pointer) in the upper (next) level. We need to calculate how many pages are required to store this next level entries (please note the entry size is always 4 bytes, i.e., the number of entries that can be stored in each page is always the number from 2) 5. So on and so forth until one directory page can hold all entries pointing to its inner level. Now, we can calculate the total number of pages required to store all page table entries
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Transcribed Image Text:Consider an operating system that uses 48-bit virtual addresses and 16KB pages. The system uses a
multi-level page table design to store all the page table entries of a process, and each page table
entry and index entry are 4 bytes in size. What is the total number of page that are required to store
the page table entries of a process, across all levels of the page table? You may follow the hint below
or finish from scratch to fill the blanks. Please show your calculations to get partial points like
2^10/2^4=2^6.
1. We need to calculate the total number of page table entries needed for a process (i.e., the total
number of pages for a process)
2. We need to calculate how many entries each page can store
3. With 1 and 2, we can calculate how many pages needed for the lowest (innermost) level
4. Each page from 3 requires an entry (pointer) in the upper (next) level. We need to calculate how
many pages are required to store this next level entries (please note the entry size is always 4 bytes,
i.e., the number of entries that can be stored in each page is always the number from 2)
5. So on and so forth until one directory page can hold all entries pointing to its inner level. Now, we
can calculate the total number of pages required to store all page table entries
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