The following reaction is used to obtain iron from iron ore. The reaction of 167 g Fe2O3 (MM = 160 g/mol) with 85.8 g CO (MM = 28 g/ma 72.3 g Fe (At at =56 g/mol) is obtained. Determine the limiting reactant and the percent yield of Fe. Fe203 (s) +3 CO(g) -2 Fe(s)+3 CO2(g) O Fe2O3 is L.R and 51.2 % O Co is LR and 63.4% O Fe;O3 is LR and 22.2 % O Fe2O3 is LR and 63.4% O co is L.R and 51.2 %

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The following reaction is used to obtain iron from iron ore.
The reaction of 167 g Fe,03 (MM = 160 g/mol) with 85.8 g CO (MM = 28 g/mol)
72.3 g Fe (At at = 56 g/mol) is obtained.
Determine the limiting reactant and the percent yield of Fe.
Fe,03(s) +3 CO(g) -2 Fe(s)+3 CO2(g)
O Fe2O3 is L.R and 51.2 %
O CO is L.R and 63.4%
O Fe;O3 is L.R and 22.2 %
O Fe2O3 is LR and 63.4%
O Co is L.R and 51.2 %
Transcribed Image Text:The following reaction is used to obtain iron from iron ore. The reaction of 167 g Fe,03 (MM = 160 g/mol) with 85.8 g CO (MM = 28 g/mol) 72.3 g Fe (At at = 56 g/mol) is obtained. Determine the limiting reactant and the percent yield of Fe. Fe,03(s) +3 CO(g) -2 Fe(s)+3 CO2(g) O Fe2O3 is L.R and 51.2 % O CO is L.R and 63.4% O Fe;O3 is L.R and 22.2 % O Fe2O3 is LR and 63.4% O Co is L.R and 51.2 %
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