The following reaction involves two sequential Heck reactions. Draw structural formu- las for each organopalladium intermediate formed in the sequence and show how the final product is formed. Note from the molecular formula given under each structural formula that this conversion corresponds to a loss of H and I from the starting material. Acetonitrile, CH,CN, is the solvent. 1% mol Pd(OAc), 4% mol Ph,P CH,CN C4H171 C4H16
The following reaction involves two sequential Heck reactions. Draw structural formu- las for each organopalladium intermediate formed in the sequence and show how the final product is formed. Note from the molecular formula given under each structural formula that this conversion corresponds to a loss of H and I from the starting material. Acetonitrile, CH,CN, is the solvent. 1% mol Pd(OAc), 4% mol Ph,P CH,CN C4H171 C4H16
Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter24: Catalytic Carbon-carbon Bond Formation
Section: Chapter Questions
Problem 24.9P
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Question
![The following reaction involves two sequential Heck reactions. Draw structural formu-
las for each organopalladium intermediate formed in the sequence and show how the
final product is formed. Note from the molecular formula given under each structural
formula that this conversion corresponds to a loss of H and I from the starting material.
Acetonitrile, CH,CN, is the solvent.
1% mol Pd(OAc),
4% mol Ph,P
CH,CN
C4H171
C4H16](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7d50630-534f-4ef5-b722-b17cf01b1378%2Fdf689d5c-3c9e-403d-9e82-1cde22498dac%2Fkz3l6rn.jpeg&w=3840&q=75)
Transcribed Image Text:The following reaction involves two sequential Heck reactions. Draw structural formu-
las for each organopalladium intermediate formed in the sequence and show how the
final product is formed. Note from the molecular formula given under each structural
formula that this conversion corresponds to a loss of H and I from the starting material.
Acetonitrile, CH,CN, is the solvent.
1% mol Pd(OAc),
4% mol Ph,P
CH,CN
C4H171
C4H16
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