() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L= 9 m and cross-sectional area A = 4 mm2 lies along the x-axis between z = 0 and x = L. The material obeys Ohm's law, and its resistivity varies along the rod according to p = Po (1- where Po = 1 x 10-42. m. The end of the rod at x = 0 is at a potential Vo = 30 V greater than the end at a = L. A) What is the total resistance, in units of 2, of the rod? Answer: B) What is the current, in units of miliamperes, in the rod? Answer:

() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L= 9 m and cross-sectional area A = 4 mm2 lies along the x-axis between z = 0 and x = L. The material obeys Ohm's law, and its resistivity varies along the rod according to p = Po (1- where Po = 1 x 10-42. m. The end of the rod at x = 0 is at a potential Vo = 30 V greater than the end at a = L. A) What is the total resistance, in units of 2, of the rod? Answer: B) What is the current, in units of miliamperes, in the rod? Answer:

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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(1) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L the x-axis between a = 7 m and cross-sectional area A = 2.5 mm2 lies along L. The material obeys Ohm's law, and its resistivity varies along the %3D 0 and z = (1) rod according top= Po where po = 2.5 x 10N. m. The end of the rod at a = 0 is at a L2 %3D potential Vo = 40 V greater than the end at z = L. A) What is the total resistance, in units of 2, of the rod? Answer: B) What is the current, in units of miliamperes, in the rod? Answer: C) What is the electric potential, in units of Volt, in the rod at z = L/2? Answer:
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option(s) will result in -2 marks. 6. The resistance of a copper wire is given by R = R, (1 + a(0 – 20)] where R, = (4.00 + 0.01)2 is the resistance of wire at 0 = 20°C. The value of resistance coefficient of copper is %3D %3D (4 x 10-3+ 1 x 10-4)/°C. It is connected with a battery of emf (10.0 + 0.1) V. (A) The resistance R at 0 = 25°C is (4.08 + 0.02)N (B) The resistance R at 0 = 50°C is (4.48 ± 0.03)N (C) The percentage error in calculation of power loss in resistance at 0 = 25°C is 3% (D) The percentage error in calculation of power loss in resistance at 0 = 50°C is 4% Space for Rough Work
Calculate the resistance of five different material wires of the same diameter and length ?(I =1A with the exception of (l =0.5A) for Nichrome)
Calculate the resistivity (p) of five different material wires of the same diameter and length ?(I =1A with the exception of (l =0.5A) for Nichrome)
Problem 3: A 1.2 g wire has a density of 2.7 g/cm3 and a resistivity of 2.7 × 10−8 Ωm. The wire has a resistance of 15 Ω. a) How long is the wire? b) The wire is made up of atoms with valence 1 and molar mass 26.98 g/mol. What is the drift speed of the electrons when there is a voltage drop of 30 V across the wire?
(a) A 35.5-m length of copper wire at 20.0°C has a radius of 0.23 mm. If a potential difference of 7.0 V is applied across the length of the wire, determine the current in the wire. (Use the values in the following table.) Resistivities and Temperature Coefficients of Resistivity for Various Materials (at 20°C) Material Silver A Copper Gold Aluminum Tungsten Iron Platinum Lead Nichrome a Carbon Germanium Silicon Glass Hard rubber Sulfur Quartz (fused) Resistivity (2. m) 1.59 x 107 1.7 x 10-8 2.44 x 10-8 2.82 x 10 5.6 x 107 10.0 x 10 11 x 10 -8 -8 0.46 -8 640 22 x 10-8 3.5 x 107 -8 -8 150 x 10- -8 -5 1010-1014 ≈1013 1015 75 x 1016 Temperature Coefficient of Resistivity [(°C)-¹] 3.8 x 10 -3 3.9 × 10-3 3.4 x 10-3 3.9 x 107 5.0 x 10 4.5 x 10-3 3.92 x 10 -3 -3 0.4 x 107 -3 3.9 × 10-3 -3 -3 -0.5 x 107 -48 x 10-3 -75 x 10-3 aA nickel-chromium alloy commonly used in heating elements. (b) If the wire is heated to 40.0°C while the 7.0-V potential difference is maintained, what is the resulting…
(1) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 9 m and cross-sectional area A = 5 mm² lles along the x-axis between x = 0 and x = L. The materlal obeys Ohm's law, and Its resistivity varies along the rod according top = po 1- where on = 3 x 104 2 · m. The end of the rod at x = 0 is at a potential V = 35 V greater than the end at x = L. A) What is the total resistance, in units of 2, of the rod? Answer: B) What is the current, In units of miliamperes, in the rod? Answer: C) What is the electric potentlal, In units of Volt, in the rod at x = L/2? Answer: D) What is the electric-field magnitude E, In units of V/m, In the rod at x = L/2? Answer:
(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 4m and cross-sectional area A = 4 mm? lies along the x-axis between a = 0 and a = L. The material obeys Ohm's law, and its resistivity (1=) varies along the rod according to p = Po where po = 4 × 10 4 2. m. The end of the rod at r = 0 is at a potential Vo = 35 V greater than the end at x = L. L² A) What is the total resistance, in units of N, of the rod? Answer: B) What is the current, in units of miliamperes, in the rod? Answer: C) What is the electric potential, in units of Volt, in the rod at a = L/2? Answer: D) What is the electric-field magnitude E, in units of V/m, in the rod at a = L/2? Answer:
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Electrical conduction is a property of ionic solutions and the conductance of such electrolytic solutions depends on the concentration of the ions and also the nature of the ions (charges and mobilities). Given that electrolyte solutions obey Ohms law – express the resistance R of a solution in ohms (Ω).
(1) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 10 m and cross-sectional area A = 4.5 mm2 lies along the x-axis between e = 0 and z = L. The material obeys Ohm's law, and its resistivity varies along the rod ~(1 -). where po = 5 x 10 4N · m. The end of the rod at z = 0 is at a potential L² according to p = Po Vo = 30 V greater than the end at z = L. B) What is the current, in units of miliamperes in the rod? Answer: