() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 9 m and cross-sectional area A = 5 mm les along the x-axis between x = () and x = L. The material obeys Ohm's law, and its resistivity varies along the rod •(1 -). according to p = Po where po = 3 × 102 · m. The end of the rod at x = 0 is at a potential Va = 35 V greater than the end at x = L. A) What is the total resistance, in units of 2, of the rod? Answer: B) What is the current, In unitS of miliamperes, in the rod? Answer: C) What is the electric potential, in units of Volt, In the rod at x = L/2? Answer:

icon
Related questions
Question
(1) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.
A rod of semiconducting material of length L = 9 m and cross-sectional area A = 5 mm² lles along the x-axis between x = 0 and x = L. The materlal obeys Ohm's law, and Its resistivity varies along the rod
according top = po
1-
where on = 3 x 104 2 · m. The end of the rod at x = 0 is at a potential V = 35 V greater than the end at x = L.
A) What is the total resistance, in units of 2, of the rod?
Answer:
B) What is the current, In units of miliamperes, in the rod?
Answer:
C) What is the electric potentlal, In units of Volt, in the rod at x = L/2?
Answer:
D) What is the electric-field magnitude E, In units of V/m, In the rod at x = L/2?
Answer:
Transcribed Image Text:(1) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 9 m and cross-sectional area A = 5 mm² lles along the x-axis between x = 0 and x = L. The materlal obeys Ohm's law, and Its resistivity varies along the rod according top = po 1- where on = 3 x 104 2 · m. The end of the rod at x = 0 is at a potential V = 35 V greater than the end at x = L. A) What is the total resistance, in units of 2, of the rod? Answer: B) What is the current, In units of miliamperes, in the rod? Answer: C) What is the electric potentlal, In units of Volt, in the rod at x = L/2? Answer: D) What is the electric-field magnitude E, In units of V/m, In the rod at x = L/2? Answer:
Expert Solution
steps

Step by step

Solved in 4 steps

Blurred answer