a rod of semiconducting meterial of length L = 3m and cross-sectioanal area A=2.5mm2 lies along the x axis between x=0 and x=L. the meterial obeys ohms law, and its resistivity varies along the rod according to p=p0(1-(x2/L2)) where p0=2.5 * 10-4 ohm*m. the end of the rod at x=0 is at a potential V0= 30 V greater than the end at x = L.   a)what is the total resistance, in units of ohm, of the rod ? b)what is the current, in units of miliamperes in the rod? c)what is the electric potential, in units of Volt in the rod at x=L/2 ? d)what is the electric field magnitude E, in units of V/m, in the rod at x=L/2 ?

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a rod of semiconducting meterial of length L = 3m and cross-sectioanal area A=2.5mm2 lies along the x axis between x=0 and x=L. the meterial obeys ohms law, and its resistivity varies along the rod according to p=p0(1-(x2/L2)) where p0=2.5 * 10-4 ohm*m. the end of the rod at x=0 is at a potential V0= 30 V greater than the end at x = L.

 

a)what is the total resistance, in units of ohm, of the rod ?

b)what is the current, in units of miliamperes in the rod?

c)what is the electric potential, in units of Volt in the rod at x=L/2 ?

d)what is the electric field magnitude E, in units of V/m, in the rod at x=L/2 ?

() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.
2.5 mm2 lies along the x-axis between r
0 and r= L. The material obeys Ohm's law, and its resistivity varies along the rod
A rod of semiconducting material of length L = 3 m and cross-sectional area A
where Po = 2.5 x 10 S. m. The end of the rod at z
L2
0 is at a potential Vo = 30 V greater than the end at z
L.
according to p = Po
A) What is the total resistance, in units of N, of the rod?
Answer
B) What is the current. in units of miliamperes in the rod?
of
Answer:
stion
C) What is the electric potential, in units of Volt in the rod at z= L/2?
Answer
ut of
estion
7
D) What is the electric-field magnitude E, in units of V/m in the rod at = L/2?
lout of
Answer
Cuestion
Transcribed Image Text:() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. 2.5 mm2 lies along the x-axis between r 0 and r= L. The material obeys Ohm's law, and its resistivity varies along the rod A rod of semiconducting material of length L = 3 m and cross-sectional area A where Po = 2.5 x 10 S. m. The end of the rod at z L2 0 is at a potential Vo = 30 V greater than the end at z L. according to p = Po A) What is the total resistance, in units of N, of the rod? Answer B) What is the current. in units of miliamperes in the rod? of Answer: stion C) What is the electric potential, in units of Volt in the rod at z= L/2? Answer ut of estion 7 D) What is the electric-field magnitude E, in units of V/m in the rod at = L/2? lout of Answer Cuestion
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