The following MINITAB output presents the results of a hypothesis test for the difference Hx - Hy between two population means: Two-sample T for X vs Y N Mean StDev SE Mean 135 3.94 2.65 0.23 180 4.43 2.38 0.18 Difference = mu (X) – mu (Y) Estimate for difference: -0.484442 95% upper bound for difference: -0.007380 T-Test of difference = 0 (vs <): T-Value = -1.68 P-Value = 0.047 DF = 270 Is this a one-tailed or two-tailed test? a. b. What is the null hypothesis? Can H, be rejected at the 5% level? How can you tell? C. d. The output presents a Student's t test. Compute the P-value using a z test. Are the two results similar? Use the output and an appropriate table to compute a 99% confidence interval for Hy- Hy based on the z statistic. e.

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The following MINITAB output presents the results of a hypothesis test for the difference
Hx - Hy between two population means:
Two-sample T for X vs Y
N
Mean
StDev
SE Mean
135
3.94
2.65
0.23
180
4.43
2.38
0.18
Difference = mu (X) – mu (Y)
Estimate for difference: -0.484442
95% upper bound for difference: -0.007380
T-Test of difference = 0 (vs <): T-Value = -1.68 P-Value = 0.047 DF = 270
Is this a one-tailed or two-tailed test?
a.
b.
What is the null hypothesis?
Can H, be rejected at the 5% level? How can you tell?
C.
d.
The output presents a Student's t test. Compute the P-value using a z test. Are the two
results similar?
Use the output and an appropriate table to compute a 99% confidence interval for Hy-
Hy based on the z statistic.
e.
Transcribed Image Text:The following MINITAB output presents the results of a hypothesis test for the difference Hx - Hy between two population means: Two-sample T for X vs Y N Mean StDev SE Mean 135 3.94 2.65 0.23 180 4.43 2.38 0.18 Difference = mu (X) – mu (Y) Estimate for difference: -0.484442 95% upper bound for difference: -0.007380 T-Test of difference = 0 (vs <): T-Value = -1.68 P-Value = 0.047 DF = 270 Is this a one-tailed or two-tailed test? a. b. What is the null hypothesis? Can H, be rejected at the 5% level? How can you tell? C. d. The output presents a Student's t test. Compute the P-value using a z test. Are the two results similar? Use the output and an appropriate table to compute a 99% confidence interval for Hy- Hy based on the z statistic. e.
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