**Statistical Analysis of Police Emergency Calls** *Overview:* Samples of 100 eight-hour shifts were randomly selected from the police records for each of two districts in a large city. The number of police emergency calls was recorded for each shift. The sample statistics are listed below: | Region | Sample Size | Sample Mean | Sample Variance | |--------|-------------|-------------|-----------------| | 1 | 100 | 2.6 | 1.24 | | 2 | 100 | 3.4 | 2.54 | *Objective:* Find a 90% confidence interval for the difference in the mean numbers of police emergency calls per shift between the two districts of the city. (Use \(\mu_1 - \mu_2\). Round your answers to two decimal places.) *Calculate the confidence interval:* [____] calls per shift to [____] calls per shift *Explanation of the Table:* - **Sample Size:** The number of shifts sampled in each region, both are 100. - **Sample Mean:** The average number of emergency calls per shift: 2.6 for Region 1, and 3.4 for Region 2. - **Sample Variance:** The measure of variability in the number of calls: 1.24 for Region 1, and 2.54 for Region 2. This analysis and calculation provide an understanding of differences in call volumes between the two districts, offering insights into resource allocation and policy-making.
**Statistical Analysis of Police Emergency Calls** *Overview:* Samples of 100 eight-hour shifts were randomly selected from the police records for each of two districts in a large city. The number of police emergency calls was recorded for each shift. The sample statistics are listed below: | Region | Sample Size | Sample Mean | Sample Variance | |--------|-------------|-------------|-----------------| | 1 | 100 | 2.6 | 1.24 | | 2 | 100 | 3.4 | 2.54 | *Objective:* Find a 90% confidence interval for the difference in the mean numbers of police emergency calls per shift between the two districts of the city. (Use \(\mu_1 - \mu_2\). Round your answers to two decimal places.) *Calculate the confidence interval:* [____] calls per shift to [____] calls per shift *Explanation of the Table:* - **Sample Size:** The number of shifts sampled in each region, both are 100. - **Sample Mean:** The average number of emergency calls per shift: 2.6 for Region 1, and 3.4 for Region 2. - **Sample Variance:** The measure of variability in the number of calls: 1.24 for Region 1, and 2.54 for Region 2. This analysis and calculation provide an understanding of differences in call volumes between the two districts, offering insights into resource allocation and policy-making.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![**Statistical Analysis of Police Emergency Calls**
*Overview:*
Samples of 100 eight-hour shifts were randomly selected from the police records for each of two districts in a large city. The number of police emergency calls was recorded for each shift. The sample statistics are listed below:
| Region | Sample Size | Sample Mean | Sample Variance |
|--------|-------------|-------------|-----------------|
| 1 | 100 | 2.6 | 1.24 |
| 2 | 100 | 3.4 | 2.54 |
*Objective:*
Find a 90% confidence interval for the difference in the mean numbers of police emergency calls per shift between the two districts of the city. (Use \(\mu_1 - \mu_2\). Round your answers to two decimal places.)
*Calculate the confidence interval:*
[____] calls per shift to [____] calls per shift
*Explanation of the Table:*
- **Sample Size:** The number of shifts sampled in each region, both are 100.
- **Sample Mean:** The average number of emergency calls per shift: 2.6 for Region 1, and 3.4 for Region 2.
- **Sample Variance:** The measure of variability in the number of calls: 1.24 for Region 1, and 2.54 for Region 2.
This analysis and calculation provide an understanding of differences in call volumes between the two districts, offering insights into resource allocation and policy-making.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb365fa56-db01-4f82-bc2c-5bb5151e447e%2Fb5604e4a-d8ac-4101-bdbd-d151f216dfc7%2Fqyqhy4_processed.png&w=3840&q=75)
Transcribed Image Text:**Statistical Analysis of Police Emergency Calls**
*Overview:*
Samples of 100 eight-hour shifts were randomly selected from the police records for each of two districts in a large city. The number of police emergency calls was recorded for each shift. The sample statistics are listed below:
| Region | Sample Size | Sample Mean | Sample Variance |
|--------|-------------|-------------|-----------------|
| 1 | 100 | 2.6 | 1.24 |
| 2 | 100 | 3.4 | 2.54 |
*Objective:*
Find a 90% confidence interval for the difference in the mean numbers of police emergency calls per shift between the two districts of the city. (Use \(\mu_1 - \mu_2\). Round your answers to two decimal places.)
*Calculate the confidence interval:*
[____] calls per shift to [____] calls per shift
*Explanation of the Table:*
- **Sample Size:** The number of shifts sampled in each region, both are 100.
- **Sample Mean:** The average number of emergency calls per shift: 2.6 for Region 1, and 3.4 for Region 2.
- **Sample Variance:** The measure of variability in the number of calls: 1.24 for Region 1, and 2.54 for Region 2.
This analysis and calculation provide an understanding of differences in call volumes between the two districts, offering insights into resource allocation and policy-making.
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