The mean tensile strengths of 4 different cotton blends (blends 1,2, 3, 4) are being compared using an Analysis of Variance (ANOVA). For each blend, a random sample of 11 fabric squares is taken. The sample variances are s = 20.0, s, = 25.5, s = 24.3, s = 30.5. Given that the value of s = 8.8, calculate the value of the ANOVA %3D size n = test statistic. Enter your answer to two decimal places. Hint: one can check by the definition that the following is true: (1) Treatment of mean squares: MSTrt = n s2. %3D (2) Error of mean squares: M SE = E, s? = s + s + s + s.

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The mean tensile strengths of 4 different cotton blends (blends 1, 2, 3, 4) are being compared using an Analysis of Variance (ANOVA). For each blend, a random sample of size \( n = 11 \) fabric squares is taken. The sample variances are \( s_1^2 = 20.0 \), \( s_2^2 = 25.5 \), \( s_3^2 = 24.3 \), \( s_4^2 = 30.5 \). Given that the value of \( s_{\bar{x}}^2 = 8.8 \), calculate the value of the ANOVA test statistic. Enter your answer to two decimal places.

**Hint**: One can check by the definition that the following is true:

1. Treatment of mean squares: \( MS_{Trt} = n \cdot s_{\bar{x}}^2 \)

2. Error of mean squares: 
   \[
   MS_E = \sum_{i=1}^{a} s_i^2 = s_1^2 + s_2^2 + s_3^2 + s_4^2
   \]
Transcribed Image Text:The mean tensile strengths of 4 different cotton blends (blends 1, 2, 3, 4) are being compared using an Analysis of Variance (ANOVA). For each blend, a random sample of size \( n = 11 \) fabric squares is taken. The sample variances are \( s_1^2 = 20.0 \), \( s_2^2 = 25.5 \), \( s_3^2 = 24.3 \), \( s_4^2 = 30.5 \). Given that the value of \( s_{\bar{x}}^2 = 8.8 \), calculate the value of the ANOVA test statistic. Enter your answer to two decimal places. **Hint**: One can check by the definition that the following is true: 1. Treatment of mean squares: \( MS_{Trt} = n \cdot s_{\bar{x}}^2 \) 2. Error of mean squares: \[ MS_E = \sum_{i=1}^{a} s_i^2 = s_1^2 + s_2^2 + s_3^2 + s_4^2 \]
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