The following MINITAB output presents the results of a hypothesis test for a populationmean µ. Some of the numbers are missing. Fill them in.One-Sample Z: XTest of mu = 3.5 vs not = 3.5The assumed standard deviation = 2.00819Variable NMeanStDev SE Mean95% CI Z Pх87 4.07114 2.00819(a) (3.64916, 4.49312) (b) (c)

The values missed in the table will be obtained as given below: (a)

Answered: The following MINITAB output presents…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Consider the following set of data. Sample Size Mean Standard Deviation Group 1 100 13,000 345 Group 2 80 12,850 500 Assume that the samples come from normal populations. Find the value of the test statistic used for testing the hypotheses Ho: 1 - 2 = 0 versus H - As 70. Ot = - 3.02 Ot = - 2.45 Ot = - 2.81 Ot = - 2.28 O None of the above.
The mean monthly electricity bill in Ghana is Ghc62.50 per household. A sample of 70 households in the Ga East district of Accra showed a sample mean of Ghc 59.20. Use a population standard deviation of σ=Ghc9.8. Which of the following indicate the form of the hypotheses test for determining whether the sample data support the conclusion that the mean monthly electricity bill in the Ga East district of Accra is less than the national mean of GHC62.50? A. H0:μ=62.50 Ha:μ≠62.50 B. H0:μ≥62.50 Ha:μ<62.50 C. H0:μ>62.50; Ha:μ≤62.50 D. H0:μ≤62.50; Ha:μ>62.50 E. H0:μ<62.50; Ha:μ≥62.50
In a random sample of 75 eighth grade students scores on a national mathematics assessment test has a mean score of 266. The test result prompts a state school administration to declare that the mean score for the stated eighth graders on this exam is more than 260. Assume the population standard deviation is 34. At a=0.09, is there enough evidence to support the administrations claim? Write the claim mathematically and identify Ho and Ha Find the standardized test statistic z, and its corresponding area
The daily sleep duration among college students is normally distributed with a mean of 8.13 and standard deviation of 1.87. You want to use a sample size such that 95% of the averages fall within ±15±15 minutes (.25 of an hour) of the true mean of 8.13. Determine the smallest number of students you need to sample.
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3.3.15 Use z scores to compare the given values. Based on sample data, newborn males have weights with a mean of 3293.7 g and a standard deviation of 551.3 g. Newborn females have weights with a mean of 3000.6 g and a standard deviation of 590.5 g Who has the weight that is more extreme relative to the group from which they came; a male who weighs 1700 g or a female who weighs 1700 g? V has the weight that is more extreme. Since the z score for the male is z= and the z score for the female isz= the (Round to two decimal places.)
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You wish to test the following claim (HaHa) at a significance level of α=0.01α=0.01. Ho:μ=81.9 Ha:μ≠81.9You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=12n=12 with mean M=72.6M=72.6 and a standard deviation of SD=7.5SD=7.5.What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = ______The p-value is... A.) less than (or equal to) αα B.) greater than α This p-value leads to a decision to... A.) reject the null B.) accept the null C.) fail to reject the null As such, the final conclusion is that... A.) There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 81.9. B.) There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 81.9. C.) The sample data support the claim that the population mean is not equal to 81.9. D.) There is not sufficient sample evidence to…
The following MINITAB output presents the results of a hypothesis test for a population mean µ. One-Sample Z: X Test of mu = 73.5 vs not = 73.5 The assumed standard deviation = 2.3634 Variable N Mean StDey SE 95% CI Mean (72.8614, –1.290.196 73.6308) 145 73.24612.3634 0.1963 Is this a one-tailed or two-tailed test? a. b. What is the null hypothesis? C. What is the P-value? d. Use the output and an appropriate table to compute the P-value for the test of Ho: µ 2 73.6 versus H1: µ < 73.6. Use the output and an appropriate table to compute a 99% confidence interval for µ. e.
During an economic crisis, the average value of homes in a community of 36 homes lost $9445 with a standard deviation of $1300. The average home value in the region lost $8990. Was this community of 36 homesunusual? Use a t-test to decide if the average loss observed was significantly different from the region value. Use a level of significance α=0.05. Identify the hypotheses for the test. H0: μ ▼ not equals≠ equals= greater than> less than< nothing HA: μ ▼ equals= greater than> not equals≠ less than< nothing The test statistic is nothing. (Round to two decimal places as needed.) The P-value is nothing. (Round to three decimal places as needed.) What is the conclusion of the test? Was the average loss observed significantly different from the region value? ▼ Reject Fail to reject the null hypothesis because the P-value is ▼ greater less than the given significance level, and conclude that the…
During an economic crisis, the average value of homes in a community of 36 homes lost $9284 with a standard deviation of $1450. The average home value in the region lost $8790. Was this community of 36 homes unusual? Use a t-test to decide if the average loss observed was significantly different from the region value. Use a level of significance α=0.05. Identify the hypotheses for the test. H0: μ ▼ less than< greater than> equals= not equals≠ nothing HA: μ ▼ less than< not equals≠ greater than> equals= nothing The test statistic is nothing. (Round to two decimal places as needed.) The P-value is nothing. (Round to three decimal places as needed.) What is the conclusion of the test? Was the average loss observed significantly different from the region value? ▼ Fail to reject Reject the null hypothesis because the P-value is ▼ greater less than the given significance level, and conclude that the…

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