The following MINITAB output display presents a 98% confidence interval for the difference between two means.ABN17Part: 0 / 325Part 1 of 3Mean72.9172Difference = mu (A) - mu (B)52.1743St Dev10.7134Estimate for difference: 20.74299.123798% CI for difference: (12.9408, 28.5450) DF = 30The point estimate of μ₁ −μ₂ is.SE MeanX2.59841.8247

Answered: The following MINITAB output display…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean noise level of 19 randomly selected areas designated as emergency rooms was 63.1 dBA and the sample standard deviation is 5.0 dBA. The mean noise level for 24 randomly selected areas designated as operating theaters was 56.3 dBA and the sample standard deviation was 7.0 dBA. An engineer reported a confidence interval of (1.8454, 11.409) for the difference in the mean noise level between areas designated as emergency rooms and areas designated for operating theaters, but neglected to specify the significance level. Estimate the significance level of the confidence interval if the population standard deviations, 01 and oz of the two populations are unknown and unequal. At the estimated significance level, could it be concluded that there is a difference in the means?
18. 6 randomly selected Ontario men gave foot size of 11.3 inches on average. Foot size of Ontario men is normally distributed with a standard deviation of 1 inches. We want to develop a 96% confidence interval for the true mean foot size of Ontario men. The critical value from the table for this confidence interval is: 3.397 1.75 2.05 2.757
An SRS of 27 students at NYU gave an average height of 5.4 feet and a standard deviation of .1 feet. Find a 90% confidence interval for the mean height of students at NYU.
If a 90% confidence interval for the mean is (75.3 to 80.9), we would reject H0:  =70 in favor of H1:  ≠ 70 at  = 0.05.
A small university is trying to monitor its electricity usage. For a random sample of 30 weekend days (Saturdays and Sundays), the student center used an average of 94.26 kilowatt hours (kWh) with standard deviation 43.29. For a random sample of 60 weekdays, (Monday - Friday), the student center used an average of 112.63 kWh with standard deviation 32.07. Construct a 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days. Use two decimal places in your margin of error. -6.80 to 43.54 kWh -4.61 to 41.35 kWh -3.38 to 40.51 kWh 0.12 to 36.62 kWh
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Suppose the mean of a given data set is 900.6 with a margin of error of 63.3.Write a confidence interval for the true mean using the margin of error given and report your answer using ±± notation.
A random sample of 78 measurements was selected from a population with ?=2.76σ=2.76. The sample mean was 122.5. Calculate a 99% confidence interval for ?
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A particular brand of petrol was used in 85 randomly chosen cars of the same model and age. The petrol consumption, x miles per gallon, was obtained for each car. The results are summarized by ∑x=1965 and ∑x2=45959. Calculate a 99% confidence interval for the mean petrol consumption of all cars of this model and age.
A random sample of 30 households was selected as part of a study on electricity usage, and the number of kilowatt-hours (kWh) was recorded for each household in the sample for March of 2006. The average usage was found to be 375kWh with a standard deviation of 81kWh. Assuming the usage is normally distributed, provide a 99% confidence interval for the mean usage in March of 2006.

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