The following mechanism has been proposed for the conversion of tert-butyl bromide to tert-butyl alcohol in aqueous solution: step 1 slow: (CH)3CB (CH3)3C* + Br step 2 fast: (CH3)3C* + OH° → (CH)¿COH (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. (2) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (3) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A]"[B]"., where '1' is understood (so don't write it) for m, n etc.) Rate =

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Chapter1: Chemical Foundations
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**Conversion of tert-Butyl Bromide to tert-Butyl Alcohol: Reaction Mechanism and Rate Law**

The following mechanism has been proposed for the conversion of tert-butyl bromide to tert-butyl alcohol in aqueous solution:

**Step 1 (slow):**
\[
\text{(CH}_3\text{)}_3\text{CBr} \rightarrow \text{(CH}_3\text{)}_3\text{C}^+ + \text{Br}^-
\]

**Step 2 (fast):**
\[
\text{(CH}_3\text{)}_3\text{C}^+ + \text{OH}^- \rightarrow \text{(CH}_3\text{)}_3\text{COH}
\]

**Questions:**

1. **What is the equation for the overall reaction?** 
   Use the smallest integer coefficients possible. If a box is not needed, leave it blank.

   \[ 
   \text{Reactants: }\_\_\_\_ + \_\_\_\_ \rightarrow \text{Products: }\_\_\_\_ + \_\_\_\_
   \]

2. **Which species acts as a reaction intermediate?** 
   Enter formula. If none, leave box blank.

   \[ 
   \text{Intermediate: }\_\_\_\_
   \]

3. **Complete the rate law for the overall reaction that is consistent with this mechanism.** 

   (Use the form \( k[\text{A}]^m[\text{B}]^n \), where '1' is understood (so don't write it) for \( m \), \( n \) etc.)

   \[ 
   \text{Rate} = \_\_\_\_
   \]
Transcribed Image Text:**Conversion of tert-Butyl Bromide to tert-Butyl Alcohol: Reaction Mechanism and Rate Law** The following mechanism has been proposed for the conversion of tert-butyl bromide to tert-butyl alcohol in aqueous solution: **Step 1 (slow):** \[ \text{(CH}_3\text{)}_3\text{CBr} \rightarrow \text{(CH}_3\text{)}_3\text{C}^+ + \text{Br}^- \] **Step 2 (fast):** \[ \text{(CH}_3\text{)}_3\text{C}^+ + \text{OH}^- \rightarrow \text{(CH}_3\text{)}_3\text{COH} \] **Questions:** 1. **What is the equation for the overall reaction?** Use the smallest integer coefficients possible. If a box is not needed, leave it blank. \[ \text{Reactants: }\_\_\_\_ + \_\_\_\_ \rightarrow \text{Products: }\_\_\_\_ + \_\_\_\_ \] 2. **Which species acts as a reaction intermediate?** Enter formula. If none, leave box blank. \[ \text{Intermediate: }\_\_\_\_ \] 3. **Complete the rate law for the overall reaction that is consistent with this mechanism.** (Use the form \( k[\text{A}]^m[\text{B}]^n \), where '1' is understood (so don't write it) for \( m \), \( n \) etc.) \[ \text{Rate} = \_\_\_\_ \]
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