Nn.26.Subject :- Chemistry The following information is given for magnesium at 1 atm:boiling point = 1.090x10³ °C AHvap(1.090×103³ °C) =melting point = 649.0 °CAHfus (649.0 °C) = 368.3 J/gspecific heat solid = 1.017 J/gºCspecific heat liquid = 1.339 J/g °C5.424x10³ J/gA 20.80 g sample of liquid magnesium at 741.0 °C is poured into a mold and allowed to cool to22.0 °C. How many kJ of energy are released in this process. Report the answer as a positivenumber.kJ

Answer: Cooling of Mg is a 3 step process: 1. Cooling of liquid Mg up to its freezing point 2.…

The following information is given for magnesium at 1 atm: boiling point = 1.090×10³ °C melting point = 649.0 °C specific heat solid = 1.017 J/gºC specific heat liquid = 1.339 J/gºC AHvap(1.090x103³ °C) = 5.424x10³ J/g AHfus (649.0 °C) 368.3 J/g = A 20.80 g sample of liquid magnesium at 741.0 °C is poured into a mold and allowed to cool to 22.0 °C. How many kJ of energy are released in this process. Report the answer as a positive number. kj

The following information is given for magnesium at 1 atm: boiling point = 1.090×10³ °C melting point = 649.0 °C specific heat solid = 1.017 J/gºC specific heat liquid = 1.339 J/gºC AHvap(1.090x103³ °C) = 5.424x10³ J/g AHfus (649.0 °C) 368.3 J/g = A 20.80 g sample of liquid magnesium at 741.0 °C is poured into a mold and allowed to cool to 22.0 °C. How many kJ of energy are released in this process. Report the answer as a positive number. kj

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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