The following histograms were derived using the same data on cycles to failure of aluminum test coupons. Compare the histograms. Do both display similar information? Histogram 8 bins: Histogram of Cycles to failure (8 bins)
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- What is the correct answer?The following histograms were created using the same motor fuel octane data. Compare the histograms. Do both display similar information? Histogram 8 bins: Histogram of Fuel (8 Bins) 30 20- 10- 84 87 93 96 102 Fuel Histogram 16 Bins: Histogram of Fuel (16 Bins) 18- 16- 14 12 10- 8- 6- 4- 2- 86.4 88.8 91.2 98.4 84.0 93.6 96.0 100.8 Fuel a. Yes, both give similar information. Both appear skewed on one side b. Similar even if different number of bins. Both are skewed to the right c. Not similar as each has different number of bins. But both show the mean at the center O d. Yes, both of them give similar information. The mean value is at the center and are both appear symmetric Auanbay AouanbaAccording to data from the Tobacco Institute Testing Laboratory, a certain brand of cigarette contains an average of 1.4 milligrams of nicotine. An advocacy group questions this figure, and commissions an independent test to see if the the mean nicotine content is higher than the industry laboratory claims. The test involved randomly selecting n = 15 cigarettes, measuring the nicotine content (in milligrams) of each cigarette. The data is given below: 1.8, 1.8, 1.5, 1.1, 1.4, 1.3, 1.3, 1.4, 1.1, 1.3, 1.6, 1.2, 1.8, 1.4, 1.6; Download .csv file Not sure how to perform some of the tasks with R-Studio? Click to learn more (a) Do the data follow an approximately Normal distribution? Use alpha = 0.05. yes (b) Determine the P-value for this Normality test, to at least three decimal places. P (c) Choose the correct statistical hypotheses. O A. Ho: > 1.4, O B. Ho = 1.4, O C. Ho X = 1.4, O D. Ho: X = 1.4, ⒸE. Ho - 1.4 HA: > 1.4 OF. Ho: X > 1.4, HA: X < 1.4 HA: < 1.4 HA: 1.4 HA: X 1.4 HA: X <…
- An experiment sought to discover if a course on nutrition would influence the Body Mass Index (BMI) of the students enrolled. Measures of body fat percentages were taken before the yearlong course and then again at the end of the course for each of the 10 students. The data are as follows: Student: 1 2 3 4 5 6 7 8 9 10 Before: 16.85 18.62 35.79 22.66 18.74 22.25 19.95 14.61 27.49 20.00 End: 16.42 18.53 36.01 22.53 18.59 22.03 19.25 14.06 26.11 19.42 Test the hypothesis at the 0.05 level of significance that the mean body fat percentages of the students decreased by the end of the course.fill blanks underlines.Can you please check my work
- Listed below are the measured radiation emissions (in W/kg) corresponding to cell phones: A, B, C, D, E, F, G, H, I, J, and K respectively. The media often present reports about the dangers of cell phone radiation as a cause of cancer. Cell phone radiation must be 1.6 W/kg or less. Find the a. mean, b. median, c. midrange, and d. mode for the data. Also complete part e. 0.32 1.49 1.41 0.27 1.08 0.77 0.55 0.22 1.17 1.28 1.06 a. Find the mean. The mean is (Round to three decimal places as needed.) ... nState the estimated coefficient for time and its interpretation. Also, state what the coefficient of determination is and its interpretation.A survey was conducted on unauthorized use of computer systems. One of the survey questions asked respondents to indicate the percentage of monetary losses attributable to malicious actions by individuals within the organization. The histogram below summarizes the data for the 121 firms who experienced some monetary loss due to malicious insider actions. a. Which measurement class contains the highest proportion of respondents? Answer 5 Question 1 b. What is the approximate proportion of the 121 organizations that reported a monetary loss (%) from malicious inside actions less than 20%? Answer 6 Question 1 c. What is the approximate proportion of the 121 organizations that reported a percentage monetary loss from malicious inside actions greater than 60%? Answer 7 Question 1
- A marketing firm is doing research for an Internet-based company. It wants to appeal to the age group of people who spend the most money online. The company wants to know if there is a difference in the mean amount of money people spend per month on Internet purchases depending on their age bracket. The marketing firm looked at two age groups, 1818-2424 years and 2525-3030 years, and collected the data shown in the following table. Let Population 1 be the amount of money spent per month on Internet purchases by people in the 1818-2424 age bracket and Population 2 be the amount of money spent per month on Internet purchases by people in the 2525-3030 age bracket. Assume that the population variances are not the same. Internet Spending per Month 1818-2424 Years 2525-3030 Years Mean Amount Spent 62.4962.49 62.8462.84 Standard Deviation 20.0420.04 15.6415.64 Sample Size 1616 2828 Step 1 of 2 : Construct a 95%95% confidence interval for the true difference…Listed below are the measured radiation emissions (in W/kg) corresponding to cell phones: A, B, C, D, E, F, G, H, I, J, and K respectively. The media often present reports about the dangers of cell phone radiation as a cause of cancer. Cell phone radiation must be 1.6 W/kg or less. Find the a. mean, b. median, c. midrange, and d. mode for the data. Also complete part e. 0.45 0.77 0.72 0.68 1.53 1.28 0.75 0.99 0.55 0.56 1.12 --..- a. Find the mean. The mean is . (Round to three decimal places as needed.)