The following equilibrium pressures were observed at a certain temperature for the reaction N₂(g) + 3H₂(g) → 2NH3(9) PNH = 3.3 × 10-² atm PN₂ = 8.8 × 10-¹ atm PH₂ = 1.5 × 10-³ atm Calculate the value for the equilibrium constant Kp at this temperature. Kp If PN₂ = 0.694 atm, PNH3 = 0.0347 atm, and PH₂ = 0.00775 atm, does this represent a system at equilibrium?

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The following equilibrium pressures were observed at a certain temperature for the reaction:

\[ \text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) \]

- \( P_{\text{NH}_3} = 3.3 \times 10^{-2} \) atm
- \( P_{\text{N}_2} = 8.8 \times 10^{-1} \) atm
- \( P_{\text{H}_2} = 1.5 \times 10^{-3} \) atm

Calculate the value for the equilibrium constant \( K_p \) at this temperature.

\[ K_p = \]

If \( P_{\text{N}_2} = 0.694 \) atm, \( P_{\text{NH}_3} = 0.0347 \) atm, and \( P_{\text{H}_2} = 0.00775 \) atm, does this represent a system at equilibrium? 

(There is a dropdown box indicating that a selection can be made, likely for the answer.)
Transcribed Image Text:The following equilibrium pressures were observed at a certain temperature for the reaction: \[ \text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) \] - \( P_{\text{NH}_3} = 3.3 \times 10^{-2} \) atm - \( P_{\text{N}_2} = 8.8 \times 10^{-1} \) atm - \( P_{\text{H}_2} = 1.5 \times 10^{-3} \) atm Calculate the value for the equilibrium constant \( K_p \) at this temperature. \[ K_p = \] If \( P_{\text{N}_2} = 0.694 \) atm, \( P_{\text{NH}_3} = 0.0347 \) atm, and \( P_{\text{H}_2} = 0.00775 \) atm, does this represent a system at equilibrium? (There is a dropdown box indicating that a selection can be made, likely for the answer.)
Expert Solution
Step 1: Consider the given information:

straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space 2 NH subscript 3 left parenthesis straight g right parenthesis

Equilibrium constant, Kp =?        

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