The following equation represents the formation of nitrogen dioxide, a major component of smog,2 NO + O2 → 2 NO2 If 0.68 mole of NO is reacted with 0.79 mole of O2 to produce NO2, the limiting reactant is The following equation represents the formation of nitrogen dioxide, a major component of smog,2 NO + O2 → 2 NO2 If 0.68 mole of NO is reacted with 0.79 mole of O2 to produce NO2, the limiting reactant is both NO and O2. NO. NO2. O2. Interpret in words the equation shown.P4O10 (s) + 6 H2O (l) → 4 H3PO4 (aq) Interpret in words the equation shown.P4O10 (s) + 6 H2O (l) → 4 H3PO4 (aq) One mole of phosphorus(X) oxide combines with six moles of water to produce four moles of solution of hydrogen phosphate. Four moles of solid phosphorus, five moles of diatomic oxygen gas, and six moles of liquid water react together to produce four moles of phosphoric acid in solution. Four atoms of phosphorus, 16 atoms of oxygen, and 12 atoms of hydrogen rearrange to produce four molecules of phosphoric acid. Zero moles of solid phosphoric oxide dissolve in six moles of water to produce four moles of phosphorous acid. One mole of solid tetraphosphorus decaoxide reacts with six moles of liquid water to produce four moles of phosphoric acid solution.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The following equation represents the formation of nitrogen dioxide, a major component of smog,

2 NO + O₂ → 2 NO₂
If 0.68 mole of NO is reacted with 0.79 mole of O₂ to produce NO₂, the limiting reactant is

both NO and O₂.

NO.

NO₂.

O₂.

Interpret in words the equation shown.

P₄O₁₀ (s) + 6 H₂O (l) → 4 H₃PO₄ (aq)

One mole of phosphorus(X) oxide combines with six moles of water to produce four moles of solution of hydrogen phosphate.

Four moles of solid phosphorus, five moles of diatomic oxygen gas, and six moles of liquid water react together to produce four moles of phosphoric acid in solution.

Four atoms of phosphorus, 16 atoms of oxygen, and 12 atoms of hydrogen rearrange to produce four molecules of phosphoric acid.

Zero moles of solid phosphoric oxide dissolve in six moles of water to produce four moles of phosphorous acid.

One mole of solid tetraphosphorus decaoxide reacts with six moles of liquid water to produce four moles of phosphoric acid solution.

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