According to the balanced reaction below, calculate the quantity of moles of NH₃ gas that form when 4.20 mol of N₂H₄ liquid completely reacts: 3 N₂H₄(l) → 4 NH₃(g) + N₂(g)

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According to the balanced reaction below, calculate the quantity of moles of NH₃ gas that form when 4.20 mol of N₂H₄ liquid completely reacts:

3 N₂H₄(l) → 4 NH₃(g) + N₂(g)

According to the balanced reaction below, calculate the quantity of moles of NH3 gas
that form when 4.20 mol of NH: liquid completely reacts:
3
N2H+(1) →
4 NH:(g) + N:(g)
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*()
28.02
4
17.04
1
6.022 x 1023
1.40
1.05
32.06
12.6
3
5.60
16.8
8.43 x 1023
3.37 x 1024
2.53 x 1024
4.20
3.15
mol N2H4
g N2
mol NH:
g N2H4
mol N2
g NH,
Transcribed Image Text:According to the balanced reaction below, calculate the quantity of moles of NH3 gas that form when 4.20 mol of NH: liquid completely reacts: 3 N2H+(1) → 4 NH:(g) + N:(g) STARTING AMOUNT ADD FACTOR ANSWER RESET *() 28.02 4 17.04 1 6.022 x 1023 1.40 1.05 32.06 12.6 3 5.60 16.8 8.43 x 1023 3.37 x 1024 2.53 x 1024 4.20 3.15 mol N2H4 g N2 mol NH: g N2H4 mol N2 g NH,
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