According to the balanced reaction below, calculate the quantity of moles of NH₃ gas that form when 4.20 mol of N₂H₄ liquid completely reacts: 3 N₂H₄(l) → 4 NH₃(g) + N₂(g)
According to the balanced reaction below, calculate the quantity of moles of NH₃ gas that form when 4.20 mol of N₂H₄ liquid completely reacts: 3 N₂H₄(l) → 4 NH₃(g) + N₂(g)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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According to the balanced reaction below, calculate the quantity of moles of NH₃ gas that form when 4.20 mol of N₂H₄ liquid completely reacts:
3 N₂H₄(l) → 4 NH₃(g) + N₂(g)
![**Stoichiometry and Chemical Reactions: Calculating Moles of Ammonia (NH₃)**
To determine the quantity of moles of NH₃ gas that form, consider the balanced chemical reaction:
\[ 3 \, \text{N₂H₄(l)} \rightarrow 4 \, \text{NH₃(g)} + \text{N₂(g)} \]
Given that 4.20 moles of N₂H₄ react completely, we need to calculate the resulting moles of NH₃.
### Diagram Explanation
**Setup Interface:**
1. **Starting Amount:**
- Input for the initial quantity of reactant, which is 4.20 moles of N₂H₄.
2. **Calculation Multiplier:**
- Use the stoichiometry relationship from the balanced equation. It involves a mathematical setup where each component of the ratio is placed in brackets:
\[ \left( \frac{4 \, \text{mol NH₃}}{3 \, \text{mol N₂H₄}} \right) \]
3. **Interactive Buttons:**
- Present values and constants that can be added to the calculation:
- Molar mass values (e.g., 28.02, 17.04).
- Conversion factors (e.g., Avogadro's number \(6.022 \times 10^{23}\)).
- Calculated results from previously entered data (e.g., 4.20, 3.15).
4. **Answer and Reset:**
- Displays the calculated answer once all parts are entered.
- A reset button to clear inputs and start anew.
This interface provides a hands-on approach to learning chemical stoichiometry, visualizing and applying mathematical relationships to balance equations and predict reaction outcomes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33b44a1b-3e14-4b60-9d56-aa6686d7bd3d%2F6a9b87fd-1fd3-4c41-a137-23cb4f0afcdb%2Fmrf6jj_processed.png&w=3840&q=75)
Transcribed Image Text:**Stoichiometry and Chemical Reactions: Calculating Moles of Ammonia (NH₃)**
To determine the quantity of moles of NH₃ gas that form, consider the balanced chemical reaction:
\[ 3 \, \text{N₂H₄(l)} \rightarrow 4 \, \text{NH₃(g)} + \text{N₂(g)} \]
Given that 4.20 moles of N₂H₄ react completely, we need to calculate the resulting moles of NH₃.
### Diagram Explanation
**Setup Interface:**
1. **Starting Amount:**
- Input for the initial quantity of reactant, which is 4.20 moles of N₂H₄.
2. **Calculation Multiplier:**
- Use the stoichiometry relationship from the balanced equation. It involves a mathematical setup where each component of the ratio is placed in brackets:
\[ \left( \frac{4 \, \text{mol NH₃}}{3 \, \text{mol N₂H₄}} \right) \]
3. **Interactive Buttons:**
- Present values and constants that can be added to the calculation:
- Molar mass values (e.g., 28.02, 17.04).
- Conversion factors (e.g., Avogadro's number \(6.022 \times 10^{23}\)).
- Calculated results from previously entered data (e.g., 4.20, 3.15).
4. **Answer and Reset:**
- Displays the calculated answer once all parts are entered.
- A reset button to clear inputs and start anew.
This interface provides a hands-on approach to learning chemical stoichiometry, visualizing and applying mathematical relationships to balance equations and predict reaction outcomes.
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