Using the following equation: 2 NaOH + H2SO4 --> 2 H2O + Na2SO4How many grams of sodium sulfate (Na2SO4) will be formed if you start with 103.4grams of NaOH and you have an excess of sulfuric acid? Round your answer to 2decimal places.Your Answer:Answerunits

1 mole of a substance is equal to its atomic mass or molecular mass expressed in grams. The atomic…

the following equation: 2 NaOF H2S04 120 + Na25O4 How many grams of sodium sulfate (Na2SO4) will be formed if you start with 103. grams of NaOH and you have an excess of sulfuric acid? Round your answer to 2 decimal places. Your Answer: Answer units

the following equation: 2 NaOF H2S04 120 + Na25O4 How many grams of sodium sulfate (Na2SO4) will be formed if you start with 103. grams of NaOH and you have an excess of sulfuric acid? Round your answer to 2 decimal places. Your Answer: Answer units

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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How many moles of calcium hydroxide are needed to generate 7.68 moles of water, according to the following equation: 3Ca(OH)₂ + 2H3PO4 → Ca3(PO4)2 + 6H₂O • Report your answer using three significant figures. Provide your answer below: mol
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Consider the chemical reaction below: Cl2 + 2Na → 2NaCl If 56.0 grams of Na are mixed with 106.4 grams of chlorine gas and 121 grams of NaCl are produced, what is the percent yield of this reaction? Note: Give the answer in integer form, not decimal (e.g. if the answer were 50.5%, enter "50.5" not "0.505").
Consider the chemical reaction below: Cl2 + 2Na → 2NaCl If 56.0 grams of Na are mixed with 106.4 grams of chlorine gas and 121 grams of NaCl are produced, what is the percent yield of this reaction? Note: Give the answer in integer form, not decimal (e.g. if the answer were 50.5%, enter "50.5" not "0.505").
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