Aqueous hydrochloric acid (HCI) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O). What is the theoretical yield of water formed from the reaction of 25.2 g of hydrochloric acid and 39.7 g of sodium hydroxide? Round your answer to 3 significant figures. Og 0 x10 X S

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**Determining Theoretical Yield: A Reaction between Hydrochloric Acid and Sodium Hydroxide**

**Problem:**

Aqueous hydrochloric acid (HCl) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O). What is the theoretical yield of water formed from the reaction of 25.2 g of hydrochloric acid and 39.7 g of sodium hydroxide?

Round your answer to 3 significant figures.

**Answer Box:**

\[ \_\_\_\_\_\_ \text{g} \]

**Options and Controls:**

- There's an input box for entering the calculated mass of water in grams.
- Options to clear, redo, or seek help are represented by buttons marked with an "X", a circular arrow, and a question mark icon, respectively.

**Interactive Elements:**

- Explanation button: Provides step-by-step guidance on how to solve the problem.
- Check button: Allows you to verify if your answer is correct.

**Instructions:**

1. Understand the balanced chemical equation for the reaction:
   
\[ \text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O} \]

2. Convert grams of reactants to moles:
   - Moles of HCl = Mass (g) / Molar Mass (HCl)
   - Moles of NaOH = Mass (g) / Molar Mass (NaOH)

3. Determine the limiting reactant by comparing the mole ratio from the balanced equation.

4. Use the mole ratio to calculate the moles of water produced.

5. Convert the moles of water to grams using the molar mass of water.

6. Enter your answer in the provided input box and round to 3 significant figures.

This exercise helps in practicing stoichiometry, involving concepts such as molar mass, mole ratio, limiting reactants, and theoretical yield calculations.
Transcribed Image Text:**Determining Theoretical Yield: A Reaction between Hydrochloric Acid and Sodium Hydroxide** **Problem:** Aqueous hydrochloric acid (HCl) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O). What is the theoretical yield of water formed from the reaction of 25.2 g of hydrochloric acid and 39.7 g of sodium hydroxide? Round your answer to 3 significant figures. **Answer Box:** \[ \_\_\_\_\_\_ \text{g} \] **Options and Controls:** - There's an input box for entering the calculated mass of water in grams. - Options to clear, redo, or seek help are represented by buttons marked with an "X", a circular arrow, and a question mark icon, respectively. **Interactive Elements:** - Explanation button: Provides step-by-step guidance on how to solve the problem. - Check button: Allows you to verify if your answer is correct. **Instructions:** 1. Understand the balanced chemical equation for the reaction: \[ \text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O} \] 2. Convert grams of reactants to moles: - Moles of HCl = Mass (g) / Molar Mass (HCl) - Moles of NaOH = Mass (g) / Molar Mass (NaOH) 3. Determine the limiting reactant by comparing the mole ratio from the balanced equation. 4. Use the mole ratio to calculate the moles of water produced. 5. Convert the moles of water to grams using the molar mass of water. 6. Enter your answer in the provided input box and round to 3 significant figures. This exercise helps in practicing stoichiometry, involving concepts such as molar mass, mole ratio, limiting reactants, and theoretical yield calculations.
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