How many grams of aluminum hydroxide is obtained from 13.7 g of aluminum sulfide? Express your answer in grams to three significant figures.

Chemistry
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How many grams of aluminum hydroxide is obtained from 13.7 g of aluminum sulfide?
Express your answer in grams to three significant figures.
Solid aluminum sulfide reacts with water to form solid aluminum hydroxide and gaseous hydrogen sulfide.
 
Solid aluminum sulfide reacts with water to form solid
aluminum hydroxide and gaseous hydrogen sulfide.
Al½S3(s) + H2O(1) → Al(OH)3 (s) +H2S(g)
Then count each kind of atom on the two sides of the equation. There are two Al atoms, three S atoms, two H
one O atom on the left side and one Al atom, three O atoms, five H atoms, and one S atom on the right side.
the number of Al atoms, place a coefficient of 2 in front of Al(OH)3:
Al, S3(s) + H2O(1) → 2Al(OH)3 (s) +H»S(g)
Now there are two Al atoms, three S atoms, two H atoms, and one O atom on the left side and two Al atoms,
eight H atoms, and one S atom on the right side. To balance the number of S atoms, place a coefficient of 3 in f
Al, S3(s) + H2O(1)
2Al(OH)3 (s) + 3H,S(g)
Now there are 2 Al atoms, 3 S atoms, 2 H atoms, and 10 atom on the left side and 2 Al atoms, 6 O atoms,
and 3 S atoms on the right side. To bring the H and O atoms into balance, place a coefficient of 6 in front of H2
Al,S3(s) + 6H2O(1) → 2Al(OH)3(s)+ 3H2S(g)
Now there are 2 Al atoms, 3 S atoms, 6 O atoms, and 12 H atoms on each side. The equation is balanced.
Part B
How many grams of aluminum hydroxide are obtained from 13.7 g of aluminum sulfide?
Express your answer in grams to three significant figures.
F ΑΣφ.
m =
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Transcribed Image Text:Solid aluminum sulfide reacts with water to form solid aluminum hydroxide and gaseous hydrogen sulfide. Al½S3(s) + H2O(1) → Al(OH)3 (s) +H2S(g) Then count each kind of atom on the two sides of the equation. There are two Al atoms, three S atoms, two H one O atom on the left side and one Al atom, three O atoms, five H atoms, and one S atom on the right side. the number of Al atoms, place a coefficient of 2 in front of Al(OH)3: Al, S3(s) + H2O(1) → 2Al(OH)3 (s) +H»S(g) Now there are two Al atoms, three S atoms, two H atoms, and one O atom on the left side and two Al atoms, eight H atoms, and one S atom on the right side. To balance the number of S atoms, place a coefficient of 3 in f Al, S3(s) + H2O(1) 2Al(OH)3 (s) + 3H,S(g) Now there are 2 Al atoms, 3 S atoms, 2 H atoms, and 10 atom on the left side and 2 Al atoms, 6 O atoms, and 3 S atoms on the right side. To bring the H and O atoms into balance, place a coefficient of 6 in front of H2 Al,S3(s) + 6H2O(1) → 2Al(OH)3(s)+ 3H2S(g) Now there are 2 Al atoms, 3 S atoms, 6 O atoms, and 12 H atoms on each side. The equation is balanced. Part B How many grams of aluminum hydroxide are obtained from 13.7 g of aluminum sulfide? Express your answer in grams to three significant figures. F ΑΣφ. m = Submit Request Answer
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