When 18.80 grams of methane (CH4) are burned (see equation below), how many moles of oxygen gas (O2) will be used? Please round your answer to two digits after the decimal point and don't forget units and substance!CH4 + 2 O2 --> CO2 + 2 H2O

Answered: When 18.80 grams of methane (CH4) are…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

When 18.80 grams of methane (CH₄) are burned (see equation below), how many moles of oxygen gas (O₂) will be used? Please round your answer to two digits after the decimal point and don't forget units and substance!

CH₄ + 2 O₂ --> CO₂ + 2 H₂O

Expert Solution

Step 1

According to the balanced chemical equation, 1 mole of methane (CH4) reacts with 2 moles of oxygen gas (O2) to produce 1 mole of carbon dioxide (CO2) and 2 moles of water (H2O).

So we can use the stoichiometry of the reaction to find out how many moles of oxygen gas are needed to react with 18.80 grams of methane:

1 mol CH4 + 2 mol O2 → 1 mol CO2 + 2 mol H2O