Fernando is doing his pre-lab homework for Chemistry. He is asked to predict how many grams of CO, are produced if 2.09 mol of HCl are reacted according to this balanced chemical equation shown. CaCO3+2 HCI - CaCl2 + CO2 + H20 He performs the following calculation. 1 molEo, 2 motHCT 44.01 g CO, 1 molEo, 2.09 motHCT x =46.0 g CO, from the coefficients of the balanced equatia On the day of the lab his group obtains 31.21 grams of CO2 as their experimental result. What is their percent yield in standard notation?
Fernando is doing his pre-lab homework for Chemistry. He is asked to predict how many grams of CO, are produced if 2.09 mol of HCl are reacted according to this balanced chemical equation shown. CaCO3+2 HCI - CaCl2 + CO2 + H20 He performs the following calculation. 1 molEo, 2 motHCT 44.01 g CO, 1 molEo, 2.09 motHCT x =46.0 g CO, from the coefficients of the balanced equatia On the day of the lab his group obtains 31.21 grams of CO2 as their experimental result. What is their percent yield in standard notation?
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:Fernando is doing his pre-lab homework for Chemistry. He is asked to predict how many grams of CO, are produced if 2.09 mol of HCl are reacted according to this balanced
chemical equation shown.
CaCO3 +2 HCI → CaCl2 + CO2 + H20
He performs the following calculation.
1molEo,
2 metHCT
2.09 motHCI x
44.01 g CO.
= 46.0 g CO,
1molEo,
of the balanced
On the day of the lab his group obtains 31.21 grams of CO2 as their experimental result. What is their percent yield in standard notation?
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