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The following diagrams show a fully fixed cantilever beam subjected to different loading cases. For each loading case calculate the value of the internal shear force (V) and bending moment (M) at points A and B. Ensure that you adopt the positive sign convention for internal forces for all questions. Given: a = 0.5 m b = 0.1 m F₁ = 800 KN F₂ = 915 KN M₁ = 450 kNm

The following diagrams show a fully fixed cantilever beam subjected to different loading cases. For each loading case calculate the value of the internal shear force (V) and bending moment (M) at points A and B. Ensure that you adopt the positive sign convention for internal forces for all questions. Given: a = 0.5 m b = 0.1 m F₁ = 800 KN F₂ = 915 KN M₁ = 450 kNm

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Find the shear force at point A, (VA) in kN. Find the bending moment at point A,(MA) in kNm. Find the shear force at point B,(VB) in kN. Find the bending moment at point B,(MB) in kNm.
Loading Case 2: a •А 0.7 m 1 m в F2
Transcribed Image Text:Loading Case 2: a •А 0.7 m 1 m в F2
The following diagrams show a fully fixed cantilever beam subjected to different loading cases. For each loading case calculate the value of the internal shear force (V) and bending moment (M) at points A and B. Ensure that you adopt the positive sign convention for internal forces for all questions. Given: a = 0.5 m b = 0.1 m F₁ = 800 KN F2 = 915 KN M₁ = 450 kNm
Transcribed Image Text:The following diagrams show a fully fixed cantilever beam subjected to different loading cases. For each loading case calculate the value of the internal shear force (V) and bending moment (M) at points A and B. Ensure that you adopt the positive sign convention for internal forces for all questions. Given: a = 0.5 m b = 0.1 m F₁ = 800 KN F2 = 915 KN M₁ = 450 kNm
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