The following data represents the number of insects counted in two different locations (A and B).Construct a 80% confidence interval for o²/02B. (round to the nearest tenth):DATA:Observation123456789LOCATIONA454532464544434948LOCATION B49414942484249471. In the answer box enter the upper confidence interval.2. Evaluate the confidence interval and indicate if the variances are (yes) or are not (no) homogeneous(yes/no; place your answer right beside the upper confidence interval. Do not leave a space between thetwo answers).

The question is about confidence interval Given : No. of obs. under location A ( nA ) = 9 No. of…

Answered: The following data represents the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Construct both a 90% and a 99% confidence interval for B1. B1 = 42, s = 8.8, SSzx = 64, n = 19 90% : < B1 < 99% : < B1 <
2. What is the 95% confidence interval for the difference in the population means using paired samples given the sample data: xd= 2.05, sd= 0.75, n=16 D. [1.65 , 2.45] B. [1.59, 2.51] A. [1.73, 2.37] C. [1.84, 2.26] 4. A test is conducted on a new drug treatment to improve patient’s memories. The scores of the 9 subjects before and after the new treatment are given on the table. Before 55 57 57 64 64 67 70 71 71 After 57 63 67 67 70 72 73 80 81 What is the 95% confidence interval for the improvement of test scores after the new treatment is given to the patients? A. [3.63 , 8.37] C. [3.35 , 8.65] B. [3.69 , 8.31] D. [3.17 , 8.83]
To test the efficacy of a new cholesterol-lowering medication, 10 people are selected at random. Each has their LDL levels measured (shown below as Before), then take the medicine for 10 weeks, and then has their LDL levels measured again (After). Subject Before After 1 188 187 2 114 125 3 167 141 4 141 109 5 151 145 6 182 152 7 193 166 8 173 154 9 135 145 10…
5. At Community Hospital, the burn center is experimenting with a new plasma compress treatment. A random sample of 316 patients with minor burns received the plasma compress treatment. Of these patients, 259 had no visible scars after treatment. Another random sample of 419 patients with minor burns received no plasma compress treatment. For this group, 94 had no visible scars after treatment. Find a 90% confidence interval for the difference between the two population proportions.
2. A Bootstrap Dotplot with 1000 samples for the correlation between commute time and commute distance in Atlanta is shown below. Find a 99% confidence interval by hand, using the percentiles method. 40 30 20 10 0 0.65 Left Tall Two Tailight Tail a. How many 0.70 0.75 0.80 dots did you count in each tail? b. Give your confidence interval here: c. Interpret the confidence interval in context. 0.85 samples-1000 0.90
A pharmaceutical company is running tests to see how well its new drug lowers cholesterol. Fourteen adults volunteer to participate in the study. The total cholesterol level of each participant (in mg/dL) is recorded once at the start of the study and then again after three months of taking the drug. The results are given in the following table. Construct a 90% confidence interval for the true mean difference between the cholesterol levels for people who take the new drug. Let Population 1 be the initial cholesterol level and Population 2 be the cholesterol level after three months. Round the endpoints of the interval to one decimal place, if necessary. Total Cholesterol Levels (in mg/dL) Initial Level Level after Three Months 190 192 230 207 206 182 229 199 224 181 195 209 226 214 190 189 224 196 219 206 185 195 208 204 194 198 225 216 Please highlight the answer
1. The data in the file represent egg and cheese symbolizes the total fat, in grams per serving, for a sample of 20 egg and cheese sandwiches from a fast food restaurant. The data are as follows: 7 8 3 5 15 21 22 24 18 33 23 31 25 19 29 29 29 30 41 55 1. Find the mean, mode and the median. 2. Construct 95% confidence interval for the population mean total fat, in grams preserving.
The weights (in pounds (lb)) of 52 randomly selected NFL football players are presented below. 305 265 287 285 290 235 300 230 195 236 244 194 190 307 218 315 265 210 194 216 255 300 315 190 185 183 313 246 212 201 308 270 241 242 306 237 315 215 200 295 187 204 257 185 255 318 230 316 200 324 245 185 We would like to construct a 90% confidence interval for the mean weight of NFL football players. Explain why it is not necessary to assess normality for this sample Write an interpretation for your confidence interval, including units if appropriate. You may round the upper and lower limits to the nearest whole number. Does the confidence interval estimate the mean weight for the sample of 52 NFL players or for the population of NFL players? Explain.
5. Listed below are the values (in dollars) that a random sample of Americans spent on fast food per month. a. Construct a 99% confidence interval of the mean value of money spent on fast food by all Americans. 100 156 67 41 78 62 112 120 70 42 89 85 96 97 11 56 100 98 80 98 20 64 101 100 15 71 35 72 121 74 b. Interpret these results with respect to the amount Americans spend on fast food.
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
create a 90% confidence interval for the following data: x = 25 n = 100
A local university administers a comprehensive examination to the candidates for B.S. degrees in Business Administration. Five examinations are selected at random and scored. The scores are shown below. Develop a 95% confidence interval estimate for the mean of the population. Assume the population is normally distributed. Grades 80 90 91 62 77 Select one: O a. 65.39 - 94.61 O b. 68.78 - 91.22 О с. O d. 67.52 - 92.48 69.48 - 90.52

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