The following data represent the Sales (in $1000) data gathered from a marketing efficacy study in Week 1 of December 2019 at a fast-food chain. Each row is an individual store that was randomly selected for this study. Sales(In_Thousands) 71.63 62.37 63.2 74.48 36.83 70.35 43.48 43.57 47.5 49.63 49.78 51.59 58.22 60.14 61.58 67.23 70.06 75.92 77.4 85.46 87.55 89.23 60.95 71.58 64.92 a. Use Excel to create a descriptive statistics table of Sales(In_Thousand) variable along with the margin of error to compute a 98% confidence interval for average sales. Using the result, fill in the blanks of the following statements rounded properly to 2 decimal places. The average (in $1000) sales is___________ The margin of error (in $1000) for 98% confidence interval is______    The lower limit (in $1000) of 98% confidence interval for average sales is________    The upper limit (in $1000) of 98% confidence interval for average sales is________ Based on your lower and upper limits of a 98% confidence interval for average sales, is it plausible that the average sales (in $1000) for all such stores be 65 in Week 1 of December? Yes or No      because ___65 is between lower and upper values. ___65 is NOT between lower and upper values. ___65 is a value in the given data. ____65 is NOT a value in the given data. __x__None of these.

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The following data represent the Sales (in $1000) data gathered from a marketing efficacy study in Week 1 of December 2019 at a fast-food chain.
Each row is an individual store that was randomly selected for this study.

Sales(In_Thousands)
71.63
62.37
63.2
74.48
36.83
70.35
43.48
43.57
47.5
49.63
49.78
51.59
58.22
60.14
61.58
67.23
70.06
75.92
77.4
85.46
87.55
89.23
60.95
71.58
64.92

a. Use Excel to create a descriptive statistics table of Sales(In_Thousand) variable along with the margin of error to compute a 98% confidence interval for average sales.
Using the result, fill in the blanks of the following statements rounded properly to 2 decimal places.

The average (in $1000) sales is___________

The margin of error (in $1000) for 98% confidence interval is______   

The lower limit (in $1000) of 98% confidence interval for average sales is________   

The upper limit (in $1000) of 98% confidence interval for average sales is________

Based on your lower and upper limits of a 98% confidence interval for average sales, is it plausible that the average sales (in $1000) for all such stores be 65 in Week 1 of December? Yes or No
    
because

___65 is between lower and upper values.

___65 is NOT between lower and upper values.

___65 is a value in the given data.

____65 is NOT a value in the given data.

__x__None of these.

1
2
3
4
5
6
7
8
9
10
12
13
A
Sales(In_Thousands) D
16
17
18
19
20
21
22
23
24
25
26
27
28
29
Ready
71.63
62.37
63.2
74.48
36.83
70.35
43.48
43.57
47.5
49.63
49.78
51.59
58.22
60.14
61.58
67.23
70.06
75.92
77.4
85.46
87.55
89.23
60.95
71.58
64.92
B
Sales
+
Accessibility: Investigate
0
0
0
0
0
10
0
0
0
0
0
10
0
0
0
10
0
0
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Type here to search
C
Frequency
Sales in $1000
01 00 1 10 in
5
OPNWA
0
100
90
80
70
60
50
40
30
10
[36.83, 47.31]
D
Histogram
(47.31, 57.79)
E
Boxplot
(57.79,68.27)
Sales in $1000
100
(68.27,78.75)
6
F
(EZ 68 52 84)
Mean
Standard Error
Median
Mode
Standard Deviation
Sample Variance
Kurtosis
Skewness
Range
Minimum
Maximum
G
Lower limit
Upper limit
Sales(In_Thousands)
Sum
Count
Confidence Level(98.0%)
t-Test: Paired Two Sample for Means
Mean
Variance
Observations
Pearson Correlation
Hypothesized Mean Difference
H
63.786
2.817921515
#N/A
63.2
14.08960758
198.5170417
-0.595149066
-0.01719769
52.4
36.83
89.23
1594.65
Sales(In Thousands)
#DIV/0!
25
7.022709799 Margin of error
63.786
198.5170417
25
53
I
D
0
0
25
E
+
Transcribed Image Text:1 2 3 4 5 6 7 8 9 10 12 13 A Sales(In_Thousands) D 16 17 18 19 20 21 22 23 24 25 26 27 28 29 Ready 71.63 62.37 63.2 74.48 36.83 70.35 43.48 43.57 47.5 49.63 49.78 51.59 58.22 60.14 61.58 67.23 70.06 75.92 77.4 85.46 87.55 89.23 60.95 71.58 64.92 B Sales + Accessibility: Investigate 0 0 0 0 0 10 0 0 0 0 0 10 0 0 0 10 0 0 0 0 0 0 0 0 0 Type here to search C Frequency Sales in $1000 01 00 1 10 in 5 OPNWA 0 100 90 80 70 60 50 40 30 10 [36.83, 47.31] D Histogram (47.31, 57.79) E Boxplot (57.79,68.27) Sales in $1000 100 (68.27,78.75) 6 F (EZ 68 52 84) Mean Standard Error Median Mode Standard Deviation Sample Variance Kurtosis Skewness Range Minimum Maximum G Lower limit Upper limit Sales(In_Thousands) Sum Count Confidence Level(98.0%) t-Test: Paired Two Sample for Means Mean Variance Observations Pearson Correlation Hypothesized Mean Difference H 63.786 2.817921515 #N/A 63.2 14.08960758 198.5170417 -0.595149066 -0.01719769 52.4 36.83 89.23 1594.65 Sales(In Thousands) #DIV/0! 25 7.022709799 Margin of error 63.786 198.5170417 25 53 I D 0 0 25 E +
70.06
75.92
77.4
85.46
87.55
89.23
60.95
71.58
64.92
Sales
Accessibility: Investigate
10
0
0
0
0
0
0
0
0
Sales in $1000
Type here to search
8888888889°
100
Et
6
Lower limit
Upper limit
t-Test: Paired Two Sample for Means
Mean
Variance
Observations
Pearson Correlation
Hypothesized Mean Difference
df
t Stat
P(T<=t) one-tail
t Critical one-tail
P(T<=t) two-tail
It Critical two-tail
Sales(In_Thousands)
63.786
198.5170417
#DIV/0!
25
53
3.827643865
0.000406775
1.71088208
0.00081355
2.063898562
D
0
0
25
Transcribed Image Text:70.06 75.92 77.4 85.46 87.55 89.23 60.95 71.58 64.92 Sales Accessibility: Investigate 10 0 0 0 0 0 0 0 0 Sales in $1000 Type here to search 8888888889° 100 Et 6 Lower limit Upper limit t-Test: Paired Two Sample for Means Mean Variance Observations Pearson Correlation Hypothesized Mean Difference df t Stat P(T<=t) one-tail t Critical one-tail P(T<=t) two-tail It Critical two-tail Sales(In_Thousands) 63.786 198.5170417 #DIV/0! 25 53 3.827643865 0.000406775 1.71088208 0.00081355 2.063898562 D 0 0 25
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