The following data represent the muzzle velocity (in feet per second) of rounds fired from a 155-mm gun. For each round, two measurements of the velocity were recorded using two different measuring devices, resulting in the following data. Complete parts (a) through (d) below. Observation 1 2 3 4 5 6 A 791.7 791.7 794.2 792.1 792.5 792.3 B 800.2 788.4 797.7 791.5 800.4 789.6 1. Why are these matched-pairs data? A.Two measurements (A and B) are taken on the same round. B.The same round was fired in every trial. C. The measurements (A and B) are taken by the same instrument. D. All the measurements came from rounds fired from the same gun. b) Is there a difference in the measurement of the muzzle velocity between device A and device B at the α=0.01 level of significance? Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers. Let di=Ai−Bi. Identify the null and alternative hypotheses. H0: μd ▼ equals= greater than> not equals≠ less than< enter your response here H1: μd ▼ greater than> less than< not equals≠ equals= enter your response here Determine the test statistic for this hypothesis test. t Subscript 0=enter your response here (Round to two decimal places as needed.) Find the critical value(s) for this hypothesis test. Round to two decimal places as needed.) What is your conclusion regarding H0? ▼ Reject Do not reject H0. There ▼ is is not sufficient evidence at the α=0.01 level of significance to conclude that there is a difference in the measurements of velocity between device A and device B. c) Construct a 99% confidence interval about the population mean difference. Compute the difference as device A minus device B. The confidence interval is (__,__) Interpret the confidence interval. A. One can be 99% confident that the mean difference in measurement is 0.01. B. One can be 99% confident that the mean difference in measurement is 0. C. One can be 1% confident that the mean difference in measurement lies in the interval found above. D. One can be 99% confident that the mean difference in measurement lies in the interval found above.

The following data represent the muzzle velocity (in feet per second) of rounds fired from a 155-mm gun. For each round, two measurements of the velocity were recorded using two different measuring devices, resulting in the following data. Complete parts (a) through (d) below. Observation 1 2 3 4 5 6 A 791.7 791.7 794.2 792.1 792.5 792.3 B 800.2 788.4 797.7 791.5 800.4 789.6 1. Why are these matched-pairs data? A.Two measurements (A and B) are taken on the same round. B.The same round was fired in every trial. C. The measurements (A and B) are taken by the same instrument. D. All the measurements came from rounds fired from the same gun. b) Is there a difference in the measurement of the muzzle velocity between device A and device B at the α=0.01 level of significance? Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers. Let di=Ai−Bi. Identify the null and alternative hypotheses. H0: μd ▼ equals= greater than> not equals≠ less than< enter your response here H1: μd ▼ greater than> less than< not equals≠ equals= enter your response here Determine the test statistic for this hypothesis test. t Subscript 0=enter your response here (Round to two decimal places as needed.) Find the critical value(s) for this hypothesis test. Round to two decimal places as needed.) What is your conclusion regarding H0? ▼ Reject Do not reject H0. There ▼ is is not sufficient evidence at the α=0.01 level of significance to conclude that there is a difference in the measurements of velocity between device A and device B. c) Construct a 99% confidence interval about the population mean difference. Compute the difference as device A minus device B. The confidence interval is (,) Interpret the confidence interval. A. One can be 99% confident that the mean difference in measurement is 0.01. B. One can be 99% confident that the mean difference in measurement is 0. C. One can be 1% confident that the mean difference in measurement lies in the interval found above. D. One can be 99% confident that the mean difference in measurement lies in the interval found above.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Question

Observation	1	2	3	4	5	6
A	791.7	791.7	794.2	792.1	792.5	792.3
B	800.2	788.4	797.7	791.5	800.4	789.6

1. Why are these matched-pairs data?

A.Two measurements (A and B) are taken on the same round.

B.The same round was fired in every trial.

C. The measurements (A and B) are taken by the same instrument.

D. All the measurements came from rounds fired from the same gun.

b) Is there a difference in the measurement of the muzzle velocity between device A and device B at the

α=0.01 level of significance? Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers.

Let

di=Ai−Bi.

Identify the null and alternative hypotheses.

H0:

μd

▼

equals=

greater than>

not equals≠

less than<

enter your response here

H1:

μd

▼

greater than>

less than<

not equals≠

equals=

enter your response here

Determine the test statistic for this hypothesis test.

t Subscript 0=enter your response here

(Round to two decimal places as needed.)

Find the critical value(s) for this hypothesis test.

Round to two decimal places as needed.)

What is your conclusion regarding H0?

▼

Reject

Do not reject H0. There

▼

is not

sufficient evidence at the α=0.01
level of significance to conclude that there is a difference in the measurements of velocity between device A and device B.

c) Construct a 99% confidence interval about the population mean difference. Compute the difference as device A minus device B.

The confidence interval is (__,__)

Interpret the confidence interval.

A. One can be 99% confident that the mean difference in measurement is 0.01.

B. One can be 99% confident that the mean difference in measurement is 0.

C. One can be 1% confident that the mean difference in measurement lies in the interval found above.

D. One can be 99% confident that the mean difference in measurement lies in the interval found above.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Expert Solution

Step by step

Solved in 5 steps with 5 images

SEE SOLUTION Check out a sample Q&A here