The following data for activated sludge process, discharge%=D10 m/min,recycle and wasted solid concentration=15000mg/L , sludge waste from theaeration tank =81.1m³/d, influent BOD concentration=160mg/L, effluent BODconcentration=4 mg/L , Oxygen transfer efficiency=8%,Qactual=........?

Solution: Given data DischargeQ=10m3/min Influent BOD concentration So=160 mg/leffluent BOD…

Answered: The following data for activated sludge…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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After primary treatment, a municipal wastewater contains 150 mg/L BOD5. The wastewater flow of 0.44 m³/s (10 MGD) is then treated in an activated sludge system with an SRT of 12 d and an HRT of 6 h. Given the biokinetic parameters tabulated below, determine the aeration volume (m³). Parameter Value 3d¹ 60 mg/L BODs 0.10 d¹ 0.6 mg VSS/mg BOD5 Hmax Ks ka Y
A centrifuge dewaters digested sludge from ananaerobic digester. Pertinent performance data are; raw sludge feed rate to the anaerobicdigester = 60,000 lb/day on a dry solids basis, digester suspended solids removalefficiency = 55 percent, suspended solids concentration in digested sludge fed to thecentrifuge = 5.0 percent by weight, centrifuge cake solids concentration = 30 percent byweight, centrifuge solids capture = 90 percent. Sketch a process flow schematic of the system showing both the digester andcentrifuge and all flowing fluid streams, clearly identify the appropriate control surface(s)for mass balance analyses, and then determine;(i) dewatered sludge mass flow rate (lb/day)(ii) centrate flow rate (gal/day)(iii) centrate suspended solids concentration (mg/l).
- An aerobic digester with a total capacity of 50,000 ft³ stabilize waste-activated sludge from an extended-aeration treatment plant without primary clarification. The average daily sludge flow pumped to the digestion tanks is 32,000 gpd with 1.5% solids, of which 65% are volatile. Calculate a) sludge detention time in the digesters b) the amount of sludge produced daily and c) the anaerobic digester dimensions. The population being served is 75,000. SS and BOD = 350 mg/l. %3D
Can you please solve step by step I can't seem to understand it.
Muni.waste.
A complete mix activated sludge process is to be used for biological treatment. This plant receives 10,000 m³ of wastewater per day with BOD loading of 250 mg/L. The primary treatment efficiency is 25%. Assume the followings: ● ● -4- Plant effluent BOD5 = 12 mg/L Biomass yield = 0.54 kg biomass / kg BOD Endogenous decay rate=0.05 day-¹ Solids Retention Time = 8 days MLVSS concentration in the aeration tank = 2,700 mg/L Waste and recycle solids concentration = 12,000 mg/L Determine the followings: (i). The hydraulic detention time in hours. (ii). The aeration tank volume in cubic meters. ...4/- SULIT EAP582
Q- ASP is used to treat a waste water flow of 2MLD having BOD5 of 250 mg/lit. The biomass concentration in the aeration tank is 2500 mg/lit and the concentration of biomass leaving the system is 80 mg/lit, the aeration tank has a volume of 200m³. Find the hydraulic retention time HRT.
Only find the BOD of the mixture.
As an operator of a wastewater treatment facility, you have learned that your plant runs well at an SRT (based on MLVSS (X) in the aeration basin) of 12 days. If today’s MLVSS (X) concentration is 2,700 mg/L and the RAS (Xr) concentration is 5,500 mg/L, how many L of sludge should you waste from the secondary clarifier today? Other design conditions: Average influent flow = 12,000 m3/d Influent soluble BOD = 150 mg/L Required effluent TSS = 30 mg/L Aeration tank Volume = 1,000 m3
Subject environmental engineering solve question 10

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The following data for activated sludge process, discharge%=D10 m/min, recycle and wasted solid concentration=15000mg/L , sludge waste from the aeration tank =81.1m³/d, influent BOD concentration=160mg/L, effluent BOD concentration=4 mg/L , Oxygen transfer efficiency=8%, Qactual=........?