P to a secondary plant that The town of Gatesville has been directed to upgrade its primary" can meet an effluent standard of 30.0 mg L-¹ BOD, and 30.0 mg L-1 suspended solids. They have selected a completely mixed activated sludge system. Assuming that the BODs of the suspended solids may be estimated as equal to 63% of the uspended solids concentration, estimate the required volume of the aeration tank. The following lata are available from the existing primary plant. Existing plant effluent characteristics Flow= 0.150 m³.s BOD, = 84.0 mg.L-1 . Assume the following values for the growth constants: K,= 100 mg L-¹ BODs: p=2.5 day-¹; =0.050 day ¹: Y=0.50 mg VSS-mg¹ BOD, removed.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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The town of Gatesville has been directed to upgrade its primary WWTP to a secondary plant that
can meet an effluent standard of 30.0 mg.L-¹ BODs and 30.0 mg.L-¹ suspended solids. They
have selected a completely mixed activated sludge system.
Assuming that the BODs of the suspended solids may be estimated as equal to 63% of the
suspended solids concentration, estimate the required volume of the aeration tank. The following
data are available from the existing primary plant.
Existing plant effluent characteristics
Flow = 0.150 m³.s¹
BOD, = 84.0 mg.L-¹
Assume the following values for the growth constants: K, = 100 mg.L-¹ BODs: pm=2.5 day-¹;
ka=0.050 day ¹; Y = 0.50 mg VSS mg ¹ BOD, removed.
Transcribed Image Text:The town of Gatesville has been directed to upgrade its primary WWTP to a secondary plant that can meet an effluent standard of 30.0 mg.L-¹ BODs and 30.0 mg.L-¹ suspended solids. They have selected a completely mixed activated sludge system. Assuming that the BODs of the suspended solids may be estimated as equal to 63% of the suspended solids concentration, estimate the required volume of the aeration tank. The following data are available from the existing primary plant. Existing plant effluent characteristics Flow = 0.150 m³.s¹ BOD, = 84.0 mg.L-¹ Assume the following values for the growth constants: K, = 100 mg.L-¹ BODs: pm=2.5 day-¹; ka=0.050 day ¹; Y = 0.50 mg VSS mg ¹ BOD, removed.
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