The following data are from a completely randomized design. Calculate the value of Fisher's LSD (to 2 decimals). Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use alpha=0.05. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers.
The following data are from a completely randomized design. Calculate the value of Fisher's LSD (to 2 decimals). Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use alpha=0.05. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers.
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Question
The following data are from a completely randomized design. Calculate the value of Fisher's LSD (to 2 decimals).
Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use alpha=0.05.
Use Fisher's LSD procedure to develop a 95% confidence

Transcribed Image Text:The following data are from a completely randomized design.
Treatment Treatment Treatment
A
B
32
44
33
30
43
36
30
44
35
26
46
36
32
48
40
Sample mean
30
45
36
Sample variance
6.00
4.00
6.50
a. At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal?
Compute the values below (to 1 decimal, if necessary),
Sum of Squares, Treatment
570
Sum of Squares, Error
66
Mean Squares, Treatment
285
Mean Squares, Error
5.5
Calculate the value of the test statistic (to 2 decimals).
51.82
The p-value is less than 0.01
What is your conclusion?
Conclude that not all treatment means are equal v
b. Calculate the value of Fisher's LSD (to 2 decimals).
Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05.
Difference Absolute Value
Conclusion
TA - EB
- Select your answer -
TA - EC
Select your answer
Select your answer
c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers.
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