The following cross-sectional areas (m2) are calculated for centre line of a drain trench at 5 m interval; 2.5 2.7 1.8 3.5 3.7 2.9 2.8 1.6 1.1 V=d[(first+last)/2)+ sum of rest cross-sectional areas] Trapezoidal formula The calculated volume in m3 of the material for the trench is: Select one: O a. 111.4 O b. 113.0 Oc 104.0 d. 118.0 Oe. 34.2 Of. None of the given answers
The following cross-sectional areas (m2) are calculated for centre line of a drain trench at 5 m interval; 2.5 2.7 1.8 3.5 3.7 2.9 2.8 1.6 1.1 V=d[(first+last)/2)+ sum of rest cross-sectional areas] Trapezoidal formula The calculated volume in m3 of the material for the trench is: Select one: O a. 111.4 O b. 113.0 Oc 104.0 d. 118.0 Oe. 34.2 Of. None of the given answers
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![The following cross-sectional areas (m2) are calculated for centre line of a drain trench at 5 m interval;
2.5 2.7 1.8 3.5 3.7 2.9 2.8 1.6 1.1
V=d[(first+last)/2)+ sum of rest cross-sectional areas] Trapezoidal formula
The calculated volume in m3 of the material for the trench is:
Select one:
O a. 111.4
O b. 113.0
Oc 104.0
O d. 118.0
Oe. 34.2
Of None of the given answers](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F245aa217-1cc8-41f0-9ede-99e060cd7ea0%2F93f055b8-1097-4956-a28a-dd8658655f03%2F130p0ug_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The following cross-sectional areas (m2) are calculated for centre line of a drain trench at 5 m interval;
2.5 2.7 1.8 3.5 3.7 2.9 2.8 1.6 1.1
V=d[(first+last)/2)+ sum of rest cross-sectional areas] Trapezoidal formula
The calculated volume in m3 of the material for the trench is:
Select one:
O a. 111.4
O b. 113.0
Oc 104.0
O d. 118.0
Oe. 34.2
Of None of the given answers
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