The following code is supposed to calculate 1/1^2 + 1/2^2 + 1/3^2 +.+ 1/9^2 + 1/10^2. However, there is a bug. In order to fix it, we need add this code, in line. Clarification: 1/2^2 means 1/4, 1/3^2 means 1/9 Note: The numbers on the left are line numbers for reference only and are not part of the code. 1 public class Example2 2{ 3 public static main (String[] args) 4 ( double sum = 0; int num = 1; 7 while (num < 10) 8 sum = sum + 1.0/(num*num); 10 11 System.out.printlin(sum); 12 } 13 }
The following code is supposed to calculate 1/1^2 + 1/2^2 + 1/3^2 +.+ 1/9^2 + 1/10^2. However, there is a bug. In order to fix it, we need add this code, in line. Clarification: 1/2^2 means 1/4, 1/3^2 means 1/9 Note: The numbers on the left are line numbers for reference only and are not part of the code. 1 public class Example2 2{ 3 public static main (String[] args) 4 ( double sum = 0; int num = 1; 7 while (num < 10) 8 sum = sum + 1.0/(num*num); 10 11 System.out.printlin(sum); 12 } 13 }
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:The following code is supposed to calculate 1/1^2 + 1/2^2 + 1/3^2 +.+ 1/9^2 + 1/10^2. However,
there is a bug. In order to fix it, we need add this code
in line
Clarification: 1/2^2 means 1/4, 1/3^2 means 1/9
Note: The numbers on the left are line numbers for reference only and are not part of the code.
1 public class Example2
2{
3 public static main (String0 args)
4 {
double sum = 0;
int num = 1;
7
while (num < 10)
8
sum = sum + 1.0/(num*num);
10
11
System.out.printin(sum);
12 }
13 }
Enter the code needed to fix the program above and the line where to insert it:
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