The following ARM instructions would store the contents of register r9 in a memory location with address given by the value in the base register, r5, plus any offset. ; let's assume that R9 has this value (doesn't work) MOV r9, #0x1A2B3C4D MOV r5, #0x08000000 STR 19, [15] STRH r9, [r5, #4] STRB r9, [r5, #6] ; store full word, no update of r5 ; store half word, no update of r5 ; store byte, no update of r5 Determine the contents of the memory locations with addresses from 0x08000000 to 0x08000006 after the code above has been executed for both big endian and little endian
The following ARM instructions would store the contents of register r9 in a memory location with address given by the value in the base register, r5, plus any offset. ; let's assume that R9 has this value (doesn't work) MOV r9, #0x1A2B3C4D MOV r5, #0x08000000 STR 19, [15] STRH r9, [r5, #4] STRB r9, [r5, #6] ; store full word, no update of r5 ; store half word, no update of r5 ; store byte, no update of r5 Determine the contents of the memory locations with addresses from 0x08000000 to 0x08000006 after the code above has been executed for both big endian and little endian
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![The following ARM instructions would store the contents of register r9 in a memory
location with address given by the value in the base register, r5, plus any offset.
; let's assume that R9 has this value (doesn't work)
MOV r9, #0x1A2B3C4D
MOV r5, #0x08000000
STR 19, [15]
STRH r9, [r5, #4]
STRB r9, [r5, #6]
; store full word, no update of r5
; store half word, no update of r5
; store byte, no update of r5
Determine the contents of the memory locations with addresses from 0x08000000 to
0x08000006 after the code above has been executed for both big endian and little endian.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F48568b67-ce78-489d-93e4-3423b29146fd%2Fc4ac32dc-d5a5-4781-92e0-fee4ac9db8dd%2F0wr5vs5_processed.png&w=3840&q=75)
Transcribed Image Text:The following ARM instructions would store the contents of register r9 in a memory
location with address given by the value in the base register, r5, plus any offset.
; let's assume that R9 has this value (doesn't work)
MOV r9, #0x1A2B3C4D
MOV r5, #0x08000000
STR 19, [15]
STRH r9, [r5, #4]
STRB r9, [r5, #6]
; store full word, no update of r5
; store half word, no update of r5
; store byte, no update of r5
Determine the contents of the memory locations with addresses from 0x08000000 to
0x08000006 after the code above has been executed for both big endian and little endian.
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