The following algorithm determines if all the numbers in the vector are different from each other, i.e. they are all distinct values. Explain when the best-case running time happens. Determine the function for this algorithm. bool all Distinct(const vector& a) { for (int i = 0; i < a.size()-1; i++) { for (int j =i+1; j < a.size(); j++){ if (a[i] == a[j]) } return false; # of primitive operations

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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The following algorithm determines if all the numbers in the vector are different from each other, i.e., they are all distinct values. Explain when the best-case running time happens. Determine the Ω function for this algorithm.

```cpp
bool allDistinct(const vector<int>& a) {

    for (int i = 0; i < a.size() - 1; i++) {

        for (int j = i+1; j < a.size(); j++) {

            if (a[i] == a[j]) 

                return false;

        }

    }

    return true;
}
```

|                  | # of primitive operations |
|------------------|---------------------------|
| (Content missing) |                           |

**Explanation:**

- **Outer Loop:** Iterates from 0 to `a.size() - 1`.
- **Inner Loop:** Starts from `i+1` up to `a.size()`.
- **Comparison:** Checks if any two elements are equal (`a[i] == a[j]`).
- **Return:** If a duplicate is found, the function returns `false`. If the loop completes, it returns `true`.

**Best-Case Scenario:**
The best-case running time occurs when the first pair `(a[i], a[j])` has an equal value, causing the algorithm to return `false` immediately. This scenario gives a best-case complexity of Ω(1) because the loop exits after the first comparison.
Transcribed Image Text:The following algorithm determines if all the numbers in the vector are different from each other, i.e., they are all distinct values. Explain when the best-case running time happens. Determine the Ω function for this algorithm. ```cpp bool allDistinct(const vector<int>& a) { for (int i = 0; i < a.size() - 1; i++) { for (int j = i+1; j < a.size(); j++) { if (a[i] == a[j]) return false; } } return true; } ``` | | # of primitive operations | |------------------|---------------------------| | (Content missing) | | **Explanation:** - **Outer Loop:** Iterates from 0 to `a.size() - 1`. - **Inner Loop:** Starts from `i+1` up to `a.size()`. - **Comparison:** Checks if any two elements are equal (`a[i] == a[j]`). - **Return:** If a duplicate is found, the function returns `false`. If the loop completes, it returns `true`. **Best-Case Scenario:** The best-case running time occurs when the first pair `(a[i], a[j])` has an equal value, causing the algorithm to return `false` immediately. This scenario gives a best-case complexity of Ω(1) because the loop exits after the first comparison.
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