The first-order rate constant for the decomposition of N₂O5, given below, at 70°C is 6.82 x 10-3 s-¹. Suppose we start with 0.0500 mol of N₂O5(g) in a volume of 2.0 L. 2 N₂O5(g) →4 NO₂(g) + O₂(9) (a) How many moles of N₂O5 will remain after 2.5 min? mol (b) How many minutes will it take for the quantity of N₂O5 to drop to 0.005 mol? min (c) What is the half-life of N₂O5 at 70°C? min

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Chapter13: Rates Of Reaction
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Problem 13.107QP
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The first-order rate constant for the decomposition of N₂O5, given below, at 70°C is 6.82 x 10-3 s-¹. Suppose we start with 0.0500 mol of N₂O5(g) in a volume of 2.0 L.
2 N₂O5(g) → 4 NO₂(g) + O₂(g)
(a) How many moles of N2O5 will remain after 2.5 min?
mol
(b) How many minutes will it take for the quantity of N₂O5 to drop to 0.005 mol?
min
(c) What is the half-life of N₂O5 at 70°C?
min
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Transcribed Image Text:The first-order rate constant for the decomposition of N₂O5, given below, at 70°C is 6.82 x 10-3 s-¹. Suppose we start with 0.0500 mol of N₂O5(g) in a volume of 2.0 L. 2 N₂O5(g) → 4 NO₂(g) + O₂(g) (a) How many moles of N2O5 will remain after 2.5 min? mol (b) How many minutes will it take for the quantity of N₂O5 to drop to 0.005 mol? min (c) What is the half-life of N₂O5 at 70°C? min Submit Answer
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