The first observation that this reaction is not a typical ligand substitution was the dependence on the pKb of the incoming ligand (using alkoxides) on the rate of substitution. It has been hypothesized that this is a base-hydrolysis mechanism. The key steps are shown below. [CoCl(NH3)5]2+ + OH– → [CoCl(NH2)(NH3)4]+ (1) [CoCl(NH2)(NH3)4]+ → [Co(NH2)(NH3)4]2+ + Cl– (2) [Co(NH2)(NH3)4]2+ + H2O → [Co(OH)(NH3)5]2+ + NH3 (3) (2) Our standard rate laws for associative and dissociative ligand substitution are rate = k[ML6][L’] and rate = k[ML6], respectively. Derive a rate law for the base-hydrolysis ligand substitution above where equation 1 is the rate determining step.
The first observation that this reaction is not a typical ligand substitution was the dependence on the pKb of the incoming ligand (using alkoxides) on the rate of substitution. It has been hypothesized that this is a base-hydrolysis mechanism. The key steps are shown below. [CoCl(NH3)5]2+ + OH– → [CoCl(NH2)(NH3)4]+ (1) [CoCl(NH2)(NH3)4]+ → [Co(NH2)(NH3)4]2+ + Cl– (2) [Co(NH2)(NH3)4]2+ + H2O → [Co(OH)(NH3)5]2+ + NH3 (3) (2) Our standard rate laws for associative and dissociative ligand substitution are rate = k[ML6][L’] and rate = k[ML6], respectively. Derive a rate law for the base-hydrolysis ligand substitution above where equation 1 is the rate determining step.
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The first observation that this reaction is not a typical ligand substitution was the dependence on the pKb of the incoming ligand (using alkoxides) on the rate of substitution. It has been hypothesized that this is a base-hydrolysis mechanism. The key steps are shown below.
[CoCl(NH3)5]2+ + OH– → [CoCl(NH2)(NH3)4]+ (1)
[CoCl(NH2)(NH3)4]+ → [Co(NH2)(NH3)4]2+ + Cl– (2)
[Co(NH2)(NH3)4]2+ + H2O → [Co(OH)(NH3)5]2+ + NH3 (3)
(2) Our standard rate laws for associative and dissociative ligand substitution are rate = k[ML6][L’] and rate = k[ML6], respectively. Derive a rate law for the base-hydrolysis ligand substitution above where equation 1 is the rate determining step.
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