The figure shows a Young's double. slit experimental setup. It is observed that when a thin transparent sheet of a co thickness t and refractive index u is put in front of one of the slits, the central maximum gets shifted by a distance equal to n fringe widths. If the wavelength of light used is λ, t will be 2nDλ (a) (b) a(μ-1) 2Dλ a(μ-1) (c) Dλ a(μ-1) (d) D Screen nDλ a(μ-1)
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- Ex. 56: In a biprism experiment interference bands are abserved at a distance of 1 m from the slit. A convex lens is put between the slit and eyepiece gives two images of slit 0.7 cm apart, the lens being 70 cm from eyepiece. Calculate the width of 100 bands, if light of wavelength 5890 A is used.An electric current through an unknown gas produces several distinct wavelengths of visible light. Consider the first order maxima for the wavelengths 403 nm, 428 nm, 511 nm, and 682 nm of this unknown spectrum, when projected with a diffraction grating of 5,000 lines per centimeter.Randomized Variablesλ1 = 403 nmλ2 = 428 nmλ3 = 511 nmλ4 = 682 nm Part (a) What would the angle (in degrees) be for the 403 nm line? Part (b) What would the angle (in degrees) be for the 428 nm line? Part (c) What would the angle (in degrees) be for the 511 nm line? Part (d) What would the angle (in degrees) be for the 682 nm line? Part (e) Using this grating, what would be the angle (in degrees) of the second-order maximum of the 403 nm line?The diffraction grating is a way of separating or dispersing light of different wavelengths, producing a spectrum of light. The grating interferes light constructively in particular directions: dsinθm=mλdsinθm=mλ For a particular angle, we calculate the wavelength. The grating constant (or line density) is 500 lines per mm -- every millimeter has 500 lines scratched onto it, equally spaced. The quantity d is the distance between the lines, and λ is the light wavelength. In the previous problem, calculate y2, where one of the second-order spots appears on the meter stick. Either that, or show that y2 can't be determined.
- An X-ray beam of wavelength 2.3 × 10-10 m makes an angle of 35° with a set of planes in a crystal which results in first order constructive interference. Determine the plane spacing in nanometers. (Please include 2 decimal places).An X-ray beam of wavelength 8.9 × 10-10 m makes an angle of 29° with a set of planes in a crystal which results in first order constructive interference. Determine the plane spacing in nanometers. (Please include 2 decimal places).Problem 7: Consider light falling on a single slit, of width 1.05 μm, that produces its first minimum at an angle of 33.6°.Randomized Variables θ = 33.6°w = 1.05 μm Calculate the wavelength of the light in nanometers.
- You measure three segments of the distance between a diffraction slit an the screen on which the pattern forms: x1 = (15.8 ± 0.2) cm, x2 = (6.7 ± 0.1) cm, and x3 = (11.3 ± 0.1). What is the uncertainty of the total distance x1 + x2 + x3? Group of answer choices 0.4 cm 0.5 cm 0.2 cm 0.3 cm 0.1 cmAngel is experimenting with a diffraction grating of unknown spacing. He is looking to determine the wavelength of the light in the emission spectrum of a gas and finds that a light having a known wavelength of 623.1nm is deflected by 43.8 ° away from the central maximum in the second order by this grating. Light of the wavelength to be measured is deflected by 45.4° away from the central maximum in the second order. What is the wavelength of this light in nanometers? Please give your answer as a whole number.To make a hologram using an Argon laser (1 = 0.488 µm), the maximum angle between objective and reference beams is 0max resolution (or spatial frequency) of the holographic recording film (fo – lines per mm)? 40°. What is the requirement on the minimum 0.633 um). Assume that z, When the hologram is reconstructed using a HeNe laser (A 10cm, z, = 2z,, Zp transversal and axial magnification (M; and Ma). = 00, please compute virtual and real image locations (Fz;), the
- There is a circular slit with its radius a = 0.1mm. The distance between the slit plane and detector plane is given by R=1m. Roughly estimate the requirement of the wavelength of incident light for Fraunhofer diffraction with appropriate justification.If the wavelength l of the Xrays is too large relative to the spacing of planes in the crystal, no Bragg diffraction will be seen because sin u would be larger than 1 in the Bragg equation, even for n 5 1. Calculate the longest wavelength of Xrays that can give Bragg diffraction from a set of planes separated by 4.20 Å.The limit to the eye's acuity is actually related to diffraction by the pupil. What is the angle between two just-resolvable points of light for a 7.25 mm diameter pupil, assuming the average wavelength of 554 nm? 0.00534 O angle between two points of light: Take the result to be the practical limit for the eye. What is the greatest possible distance a car can be from a person if he or she can resolve its two headlights, given they are 1.50 m apart? greatest distance at which headlights can be distinguished: m 1.61 Incorrect What is the distance between two just-resolvable points held at an arm's length (0.900 m) from a person's eye? 0.145 distance between two points 0.900 m from a person's eye: m Incorrect