There is a circular slit with its radius a = 0.1mm. The distance between the slit plane and detector plane is given by R=1m. Roughly estimate the requirement of the wavelength of incident light for Fraunhofer diffraction with appropriate justification.
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Q: Homework 13, Problem 6
A: Approach to solving the question:Please see attached photos for the detailed solutions. Thank you.…
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- Problem 6: A red laser (1 = 597 nm) is incident on a diffraction grating that has n= 1100 lines per c Randomized Variables 1= 597 nm n = 1100 lines/cm Part (a) What is the angle, in radians, that the first order maximum makes, 0,? 61 = sin() cos() tan() 7 8 HOME cotan() asin() acos) E 4 5 6 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() END Degrees Radians VOl BACKSPACE CLEAR DEL Submit Hint Feedback I give up! Part (b) What is the angle of the fourth order maximum, O4, in radians? +In Young's double slit experiment, the slits are 2mm apart and are illuminated by photons of two wavelengths 4, =12000Å and 1, =10000 Å . At what minimum distance from the common central bright fringe on the screen 2m from the slit will a bright fringe from one interference pattern coincide with a bright fringe from the other? (1) 8mm (2) 6mm| (3) 4mm (4) 3mmAn astronaut on the International Space Station (ISS) is experimenting with a solid-state green laser communications system from on-orbit at 435 km altitude to the earth's surface with a wavelength of 532nm and beam divergence (width) of 10 radians or 5.73 x 10-150 << 1°. The indices of refraction in free space and the atmosphere are no = 1.00000 ..., and na = 1.000293. Although density in the atmosphere varies continuously from the thinness of the upper atmosphere (near p → 0) to higher density at the surface, refraction can be modeled as a “surface' mid-atmosphere just like classic Snell's Law calculations. (d) What is the refracted wavelength, and the speed of the laser beam in air? (e) If the communications bit rate is the inverse of the laser frequency period [s], what is this bit rate?
- Figure 3.22 shows an x-ray diffraction pattern for a-iron taken using a diffractometer and monochromatic x-radiation having a wave- length of 0.1542 nm; each diffraction peak on the pattern has been indexed. Compute the interplanar spacing for each set of planes in- dexed; also determine the lattice parameter of Fe for each of the peaks. Figure 3.22 Diffraction pattern for polycrystalline a-iron. (110) (211) (200) 20.0 30.0 40.0 50.0 60.0 70.0 80.0 90.0 100.0 Diffraction angle 20 Intensity (rel ative)A parallel beam of monochromatic light of wavelength 500nm passes through a slit of width 0. 5mm. Find the angular divergence in which most of the light is diffracted.X - rays of wavelength 0.140 nm are reflected from a certain crystal, and the first - order maximum occurs at an angle of 14.4°. What value does this give for the interplanar spacing of the crystal?
- You measure the distance between the finges of a diffraction pattern as follows: Distance (mm): 3.01, 3.27, 3.28 You measure the distance eight additional times to obtain the following ten values: Distance (mm): 3.01, 3.27, 3.28, 3.31, 3.16, 3.17, 3.15, 3.25, 3.18, 1.46 What values for the distance and uncertainty would you report using the first three measurements and the entire set of ten measurements? Group of answer choices First three: (3.22 ± 0.03) mm, All ten: (3.22 ± 0.02) mm First three: (3.19 ± 0.09) mm, All ten: (3.0 ± 0.2) mm First three: (3.186667 ± 0.07216237) mm, All ten: (3.201000 ± 0.02613236) mm First three: (3.216667 ± 0.02880329) mm, All ten: (3.216000 ± 0.02379916) mm First three: (3.240000 ± 0.04082483) mm, All ten: (3.217000 ± 0.02702036) mm First three: (3.24 ± 0.04) mm, All ten: (3.22 ± 0.03) mmLight from a slit passes through a transmission diffraction grating of 400 lines/mm, which is located 3.0 m from a screen. What are the distances on the screen (from the unscattered slit image) of the three brightest visible (fi rst-order) hydrogen lines?The dispersion curve of glass is the curve that describes how the index of refraction of glass changes as a function of the wavelength. This curve can be represented approximately by Cauchy's empirical equation, n = A + B/2² where for a specific glass in question A = 1.40 and B = 2.5 × 10 nm² (yes, those units are nanometer squared). Find the phase and group velocities for light of 500nm wavelength in that glass.
- PROBLEM For a given x-ray diffraction test (n = 1) on a cubic crystal structure, the recorded diffraction peaks (20) were 24.09°, 34.33°, 42.37°, 49.33°, 55.62°, and 61.48°. The x-ray wavelength used in the test was 0.15418 nm. For this test, determine the crystal structure of the element, the lattice constant, and identify the element.Incident nA = SQ + QT (3.19) na = dnki sin 0+ dnki sin 0 (3.20) = 2drki sin 0 H.W. Derive equation 3.20 (Bragg's Law) from equation 3.19 using trigonometry formulas.If the wavelength l of the Xrays is too large relative to the spacing of planes in the crystal, no Bragg diffraction will be seen because sin u would be larger than 1 in the Bragg equation, even for n 5 1. Calculate the longest wavelength of Xrays that can give Bragg diffraction from a set of planes separated by 4.20 Å.