The figure shows a wire segment of length As = 3.5 cm, centered at the origin, carrying current i = 5.0 A in the positive y direction (as part of some complete circuit). To calculate the magnitude of the magnetic field B produced by the segment at a point several meters from the origin, we can use the Biot-Savart law as B = (uo/4n)i As (sin 0)/r2. This is because rand 0 are essentially constant over the segment. Calculate B (in unit-vector notation) at the (x, y, z) coordinates (a) (0, 0, 6.2 m), (b) (0, 7.9 m, 0), (c) (9.6 m, 8.6 m, D), and (d) (-5.1 m,-5.6 m,0).

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### Calculation of Magnetic Field Using Biot-Savart Law

The figure shows a wire segment of length \( \Delta s = 3.5 \, \text{cm} \), centered at the origin, carrying a current \( i = 5.0 \, \text{A} \) in the positive \( y \)-direction (as part of some complete circuit). 

To calculate the magnitude of the magnetic field \( \vec{B} \) produced by the segment at a point several meters from the origin, we can use the Biot-Savart Law:
\[ B = \left( \frac{\mu_0}{4 \pi} \frac{i \Delta s \sin \theta}{r^2} \right). \]

This equation applies because \( r \) and \( \theta \) are essentially constant over the segment. 

Your task is to calculate \( \vec{B} \) (in unit-vector notation) at the \( (x, y, z) \) coordinates:

- (a) \( (0, 0, 6.2 \, \text{m}) \)
- (b) \( (0, 7.9 \, \text{m}, 0) \)
- (c) \( (9.6 \, \text{m}, 8.6 \, \text{m}, 0) \)
- (d) \( (-5.1 \, \text{m}, -5.6 \, \text{m}, 0) \)

#### Diagram Explanation
The diagram indicates:

1. **Wire Segment**: A straight line along the y-axis, with a current \( i \) flowing in the positive \( y \)-direction.
2. **Coordinate system**: \( x, y, z \) axes are shown where the wire segment lies along the \( y \)-axis.
3. **Measurement of \( \Delta s \)**: It is a small segment marked on the wire's direction.

#### Calculations

(a) \( \vec{B} (0, 0, 6.2 \, \text{m}) = (\text{Number} \, \text{Units}) \hat {i} \) 

(b) \(\vec{B}  (0, 7.9 \, \text{m}, 0) = \text{Number
Transcribed Image Text:### Calculation of Magnetic Field Using Biot-Savart Law The figure shows a wire segment of length \( \Delta s = 3.5 \, \text{cm} \), centered at the origin, carrying a current \( i = 5.0 \, \text{A} \) in the positive \( y \)-direction (as part of some complete circuit). To calculate the magnitude of the magnetic field \( \vec{B} \) produced by the segment at a point several meters from the origin, we can use the Biot-Savart Law: \[ B = \left( \frac{\mu_0}{4 \pi} \frac{i \Delta s \sin \theta}{r^2} \right). \] This equation applies because \( r \) and \( \theta \) are essentially constant over the segment. Your task is to calculate \( \vec{B} \) (in unit-vector notation) at the \( (x, y, z) \) coordinates: - (a) \( (0, 0, 6.2 \, \text{m}) \) - (b) \( (0, 7.9 \, \text{m}, 0) \) - (c) \( (9.6 \, \text{m}, 8.6 \, \text{m}, 0) \) - (d) \( (-5.1 \, \text{m}, -5.6 \, \text{m}, 0) \) #### Diagram Explanation The diagram indicates: 1. **Wire Segment**: A straight line along the y-axis, with a current \( i \) flowing in the positive \( y \)-direction. 2. **Coordinate system**: \( x, y, z \) axes are shown where the wire segment lies along the \( y \)-axis. 3. **Measurement of \( \Delta s \)**: It is a small segment marked on the wire's direction. #### Calculations (a) \( \vec{B} (0, 0, 6.2 \, \text{m}) = (\text{Number} \, \text{Units}) \hat {i} \) (b) \(\vec{B} (0, 7.9 \, \text{m}, 0) = \text{Number
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