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A 5.9 kg object is moving in the positive x direction. When it passes through x = 0, a constant force directed along the axis begins to act on it. The figure here gives its kinetic energy K versus position x as it moves from x = 0 to x = 5.0 m; Ko = 29 J. The force continues to act. What is speed v when the %3D object moves back through x = -3.4 m?

A 5.9 kg object is moving in the positive x direction. When it passes through x = 0, a constant force directed along the axis begins to act on it. The figure here gives its kinetic energy K versus position x as it moves from x = 0 to x = 5.0 m; Ko = 29 J. The force continues to act. What is speed v when the %3D object moves back through x = -3.4 m?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A 5.9 kg object is moving in the positive x direction. When it passes through x = 0, a constant force directed along the axis begins to act on it. The figure here gives its kinetic energy K versus position x as it moves from x = 0 to x = 5.0 m; Ko = 29 J. The force continues to act. What is speed v when the object moves back through x = -3.4 m? K (J) Ko ·x (m) Number 2.58 Unit m/s
Transcribed Image Text:A 5.9 kg object is moving in the positive x direction. When it passes through x = 0, a constant force directed along the axis begins to act on it. The figure here gives its kinetic energy K versus position x as it moves from x = 0 to x = 5.0 m; Ko = 29 J. The force continues to act. What is speed v when the object moves back through x = -3.4 m? K (J) Ko ·x (m) Number 2.58 Unit m/s
Your answer is partially correct. A 5.9 kg object is moving in the positive x direction. When it passes through x = 0, a constant force directed along the axis begins to act on it. The figure here gives its kinetic energy K versus position x as it moves from x = 0 to x = 5.0 m; Ko = 29 J. The force continues to act. What is speed v when the object moves back through x = -3.4 m? К () Ko ·x (m) Number i 3.345 Unit m/s eTextbook and Media GO Tutorial
Transcribed Image Text:Your answer is partially correct. A 5.9 kg object is moving in the positive x direction. When it passes through x = 0, a constant force directed along the axis begins to act on it. The figure here gives its kinetic energy K versus position x as it moves from x = 0 to x = 5.0 m; Ko = 29 J. The force continues to act. What is speed v when the object moves back through x = -3.4 m? К () Ko ·x (m) Number i 3.345 Unit m/s eTextbook and Media GO Tutorial
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