The figure shows a flat sheet with a surface charge density σ =2.1 ×10−9 C/m2. A closed cubical surface (with sides L =4.5 m) encloses a part of the sheet (shaded in gray). What is the total electric flux through the sides of the cube? (a) 2.403×103 N/(C m2) (b) 0.000 N/(C m2) (c) 1.081×104 N/(C m2) (d) 2.162×104 N/(C m2) (e) 4.805×103 N/(C m2)
The figure shows a flat sheet with a surface charge density σ =2.1 ×10−9 C/m2. A closed cubical surface (with sides L =4.5 m) encloses a part of the sheet (shaded in gray). What is the total electric flux through the sides of the cube? (a) 2.403×103 N/(C m2) (b) 0.000 N/(C m2) (c) 1.081×104 N/(C m2) (d) 2.162×104 N/(C m2) (e) 4.805×103 N/(C m2)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The figure shows a flat sheet with a surface charge density σ =2.1 ×10−9 C/m2. A closed cubical surface (with sides L =4.5 m) encloses a part of the sheet (shaded in gray). What is the total electric flux through the sides of the cube?
(a) 2.403×103 N/(C m2)
(b) 0.000 N/(C m2)
(c) 1.081×104 N/(C m2)
(d) 2.162×104 N/(C m2)
(e) 4.805×103 N/(C m2)

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Expert Solution

Step 1
Given:
The charge density σ =2.1 ×10−9 C/m2.
The side is L =4.5 m.
The expression for flux through side of the cube is:
Here, is the permittivity constant whose value is 8.854X10-12 C2/Nm2.
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