The figure shows a flat sheet with a surface charge density σ =2.1 ×10−9 C/m2. A closed cubical surface (with sides L =4.5 m) encloses a part of the sheet (shaded in gray). What is the total electric flux through the sides of the cube? (a) 2.403×103 N/(C m2) (b) 0.000 N/(C m2)  (c) 1.081×104 N/(C m2) (d) 2.162×104 N/(C m2) (e) 4.805×103 N/(C m2)

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The figure shows a flat sheet with a surface charge density σ =2.1 ×10−9 C/m2. A closed cubical surface (with sides L =4.5 m) encloses a part of the sheet (shaded in gray). What is the total electric flux through the sides of the cube?
(a) 2.403×103 N/(C m2)
(b) 0.000 N/(C m2)
 (c) 1.081×104 N/(C m2)
(d) 2.162×104 N/(C m2)
(e) 4.805×103 N/(C m2)

 

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Expert Solution
Step 1

Given:

The charge density σ =2.1 ×10−9 C/m2.

The side is L =4.5 m.

The expression for flux through side of the cube is:

ϕ=12qεoϕ=12σL2εo

Here, εo is the permittivity constant whose value is 8.854X10-12 C2/Nm2.

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