The figure shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (2). The voltage drop across the capacitor is Q/C,where Q is the charge (in coulombs), so in this case Kirchhoff's Law givesRI += E(t).But I = dQ/dt (see this example from a previous section), so we haveDPRdt= E(t).Suppose the resistance is 2 N, the capacitance is 0.01 F, the electromotive force is E(t) = 70 sin(60t) V, and the initial charge is Q = 0 C.Find the charge Q at time t.Q =- e10Find the current I at time t.-50tI = 35e

When no current flows, the electromotive force (EMF) equals the difference in terminal potential.…

The figure shows a circuit containing an electromotive force, a capacitor with a capa where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives RI + 2 - E(t). But I = dQ/dt (see this example from a previous section), so we have R. = E(t).

The figure shows a circuit containing an electromotive force, a capacitor with a capa where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives RI + 2 - E(t). But I = dQ/dt (see this example from a previous section), so we have R. = E(t).

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

The figure shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (2). The voltage drop across the capacitor is Q/C,
where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives
RI +
= E(t).
But I = dQ/dt (see this example from a previous section), so we have
DP
R
dt
= E(t).
Suppose the resistance is 2 N, the capacitance is 0.01 F, the electromotive force is E(t) = 70 sin(60t) V, and the initial charge is Q = 0 C.
Find the charge Q at time t.
Q =
- e
10
Find the current I at time t.
-50t
I = 35e

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