The figure (Figure 1) shows a portion of a silver ribbon with z₁ = 14.0 mm and y₁ = 0.23 mm, carrying a current of 140 A in the +- direction. The ribbon lies in a uniform magnetic field, in the y-direction, with magnitude 0.94 T Apply the simplified model of the Hall effect. Figure B < 1 of 1 > Part A If there are 5.75-1028 free electrons per cubic meter, find the magnitude of the drift velocity of the electrons in the 2-direction. Express your answer meters per second. vd = Part B m/s Find the magnitude of the electric field in the 2-direction due to the Hall effect Express your answer volts per meter. E= V/m

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The figure (Figure 1) shows a portion of a silver ribbon with z₁ = 14.0
mm and y₁ = 0.23 mm, carrying a current of 140 A in the +-
direction. The ribbon lies in a uniform magnetic field, in the y-direction,
with magnitude 0.94 T Apply the simplified model of the Hall effect.
Figure
17
< 1 of 1
>
Part A
If there are 5.75-1028 free electrons per cubic meter, find the magnitude of the drift velocity of the electrons in the 2-direction.
Express your answer in meters per second.
vd =
Part B
Find the magnitude of the electric field in the 2-direction due to the Hall effect.
Express your answer in volts per meter.
E=
V/m
Transcribed Image Text:The figure (Figure 1) shows a portion of a silver ribbon with z₁ = 14.0 mm and y₁ = 0.23 mm, carrying a current of 140 A in the +- direction. The ribbon lies in a uniform magnetic field, in the y-direction, with magnitude 0.94 T Apply the simplified model of the Hall effect. Figure 17 < 1 of 1 > Part A If there are 5.75-1028 free electrons per cubic meter, find the magnitude of the drift velocity of the electrons in the 2-direction. Express your answer in meters per second. vd = Part B Find the magnitude of the electric field in the 2-direction due to the Hall effect. Express your answer in volts per meter. E= V/m
→ Part D
Find the Hall emf.
&Hall =
V
Transcribed Image Text:→ Part D Find the Hall emf. &Hall = V
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