Question 1: A point charge of value q= 3.10μC has a speed of t -0.81 x 107 when it is at the point (0 cm, 0 cm, 0 cm). What is the magnetic field vector in component form at position (1cm, 1cm, 0cm)? Answer Magnetic Field Vector Ho= 4T 10-7 T m² m C S Cloctric Potential from Point Charges
Q: A 5 T uniform magnetic field is oriented horizontally with respect to this page. A 3.0×10^ -6 C…
A: Field, B = 5 T Charge, q = 3×10-6 C Velocity, v = 1000 m/s Angle between field and velocity, θ = 90°
Q: An electron moves with a velocity of v⃗ =(4i^−5j^+2k^ ) m/s in a region in which the magnetic field…
A:
Q: A -1,507.9 uC charge is moving in a uniform magnetic field = (13.2,41.8,43) T with a velocity =…
A: When a charged particle q moving with velocity v through a magnetic field B , The force applied on…
Q: Find the direction of the force for the following charges moving through magnetic fields,
A: Let ... Outward direction is +z axis ..(outward to the plane) Inward direction is -zaxis ..(inward…
Q: A dc power line for a light-rail system carries 1000A at an angle of 30.0° to Earth's 5.0 x 10-5T…
A: Solution:-Given thatCurrent (I)=1000 AAngle (θ)=30°magnetic field (B)=5×10-5 TLength (L)=100 m
Q: A physicist performing a sensitive measurement wants to limit the magnetic force on a moving point…
A: solution is given as
Q: An electron travels at a speed of 9.5 x 106 m/s in a magnetic field of 1.16 x 10-3 T. As result of…
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Q: An alpha particle has a charge of +3.2 x 10-19 C and mass 6.64 x 10-27 kg. The particle is moving…
A: We have Charge q = 3.2 × 10-19 C Mass m = 6.64 × 10-27 kg Velocity v = 2.5 × 106 m/s ( to the…
Q: A 2.50-kg metallic ball at rest is being pulled by a strange magnetic field of a comet. The force…
A: Given: F = -kre-αrk = 8 N/mα=2 m-1
Q: An electron enters a region that contains a magnetic field directed into the page as shown. The…
A: Given dataAngle of the electron: θ=30°Magnetic field is into the page The charge on an electron is:…
Q: A beam of electrons moving with speed v = 2.6 × 107m/s enter and then leave the rectangular region…
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Q: A particle with a charge of Q = +1 µC has a velocity of 2x10' m/s at an angle of 30 degrees with…
A: force on a moving charge F = q v B Sin θ θ= angle between v and B DIRECTION OF FORCE = V X B…
Q: A calcium-40 ion has a positive charge that is double the charge of a proton, and a mass of 6.64 ✕…
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Q: 1. A proton is entering magnetic field B 0.2 i-0.5 j+ 0.4 k. If the proton moves at v (4000i + 5000…
A: To find the force vector acting on the proton
Q: Kieran measures the magnetic field of an electron beam. The beam strength is such that 1.90 x 1011…
A: Given data: The charge, q=1.90×1011electrons=1.90×1011×1.6×10-19 C=3.04×10-8 C The time t=1.30…
Q: A -1,688.2 uC charge is moving in a uniform magnetic field = (28.1,31.4,46.6) T with a velocity =…
A: Given Charge ,q = -1688.2 uC Magnetic field, B = ( 28.1,31.4, 46.6)T Velocity ,v = (-149,0, 100)…
Q: 4 x 1021 electrons pass through the cross-section of a wire with a cross-sectional area of 8 mm2 in…
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Q: The diagram shows a beam of ions of charge, 61 x 10-19 c that are traveling at an unknown speed. The…
A: Given, Mass=5.5×10^5kg Charge=1.61×10^-19c Magnetic field=2.20T Radius=9cm
Q: An electron traveling with a velocity of 6.0 x 105 m/s along the y direction enters a uniform…
A: Given Velocity of electron = v = 6.0 × 105 m/s in y Strength of magnetic field = B = 0.60 T in x We…
Q: A negatively charged ion with an excess electron moving with a velocity vx = 1.095 x103 m/s is…
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Q: A particle with a charge of -1.24x10-8 C is moving with instantaneous velocity = (4.19×10¹ m/s)i +…
A: Given data : Charge on particle q = -1.24 × 10-8 C Velocity of charge particle v = (4.19 × 104…
Q: A 2.50-kg metallic ball at rest is being pulled by a strange magnetic field of a comet. The force…
A:
Q: n electron moves along the z-axis with v₂ = 4.7 x 107 m/s. s it passes the origin, what are the…
A: We are given the velocity of the electron. We know that the magnetic field at a point due to charge…
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- A particle with a mass of 1.95×10−4 kgkg carries a negative charge of -4.00×10−8 CC. The particle is given an initial horizontal velocity that is due north and has a magnitude of 4.48×104 m/sm/s. What is the magnitude of the minimum magnetic field that will keep the particle moving in the earth's gravitational field in the same horizontal, northward direction?A proton (proton charge = +1.60 x 10-19 C) is moving at 290000 m/s in the negative x direction. A magnetic field of 0.700 T is oriented in the positive y direction. What is the magnetic force on the proton?A magnet produces a 0.300 T field between its poles, directed to the east. A dust particle with charge q = −3.90 × 10−18 C ismoving straight down at 0.300 cm/s in this field. What is the magnitude of the magnetic force on the dust particle?
- charge ??=1.6×10−19qp=1.6×10−19 that moves at right angles to the direction of a uniform magnetic field of strength 87.8 mT , if the magnetic force on particle is 4×10−134×10−13 N. Give your answer in km s-1What would be the magnitude and direction of force FB on a test positive charge (q = + 3e, me = 29.1 x 10-31 kg) shot in the -y direction with a speed of 7.7 x 105 m/s in a uniform magnetic field B = 2.6 x 10-4 T along +y direction? O FB = 1.97 x 10-¹7 N toward us, away from the plane of the screen O FB = 7.4 x 10-13 N away from us, towards the plane of the screen O FB = 4.92 x 10-11 N away from us, towards the plane of the screen FB = 0.00 N so will maintain its velocity.At one instant, a proton is at the origin with a velocity (9 × 106, 8 × 106, 4 × 106) m/s. At the observation location (6 × 10-8,3 × 10-8,6 × 10-8) m. A. What is the electric field due to the proton? ( B. What is the magnetic field due to the proton?
- An electron experiences the greatest force as it travels 3.7x106 m/s in a magnetic field when it is moving northward. The force is vertically upward and of magnitude 7.1x10-13N. (a)What is the direction of the magnetic field? (b)What is the magnitude of the magnetic field?A force F = ( 6×10^-3 N)i - (4×10^-3 N)j - (8×10^-3 N)k is acting on a charge q = -2×10^-9 C moving inside a uniform magnetic field with a velocity v =(2×10^6m/s) i +(3×10^6m/s) j. Calculate the components of the magnetic field knowing that the x-component of the field is equal to zero.A magnetic field near a wire varies according to the equation B = mol/2pr, where mo = 4p(10) - Tm/A. The field at point P is 20 mT. What is the field at point Q which is 4 times as far from the wire as point P? 5 mT 320 mT 80 mT 1.25 mT
- What is the force on an electron moving in the negative z direction with a speed of 4.1 x 106 m/s in a magnetic field of (-3.6,5.2,-2.8) mT? Give the answer as a vectorAn electron (electron charge = -1.60 x 10-19 C) is moving at 370000 m/s in the positive x direction. A magnetic field of 0.700 T is oriented in the positive z direction. What is the magnetic force on the electron? 4.14 x 10-14 N in the positive y direction 4.14 x 10-14 N in the negative x direction 4.14 x 10-14 N in the negative y direction 4.14 x 10-14 N in the negative z direction No magnetic force is experienced by the electron. 4.14 x 10-14 N in the positive z direction 4.14 x 10-14 N in the positive x directionA charge q = 4 µC moves with velocity v = 30 i km/s in a magnetic field B = (0.2 j + 0.5 k) T. Find the magnetic force on the charge. (24 j + 60 k) mN (−24 j + 60 k) mN 65 i mN (−60 j + 24 k) mN (60 j − 24 k) mN