**Text Transcription for Educational Website**---The accompanying figure shows a cross-section of a long, hollow, cylindrical conductor of inner radius \( r_1 = 2.5 \, \text{cm} \) and outer radius \( r_2 = 6 \, \text{cm} \). A 57-A current distributed uniformly over the cross-section flows into the page. Calculate the magnetic field at \( r = 1.5 \, \text{cm}, r = 4 \, \text{cm}, \) and \( r = 6.5 \, \text{cm} \).**Hints**- **a.** Magnetic field at \( r = 1.5 \, \text{cm} \) is \(\_\_\_\_\_\_\_\_\_) - [Additional hint for (a)]- **b.** Magnetic field at \( r = 4 \, \text{cm} \) is \(\_\_\_\_\_\_\_\_\_) - [Additional hint for (b)]- **c.** Magnetic field at \( r = 6.5 \, \text{cm} \) is \(\_\_\_\_\_\_\_\_\_) - [Additional hint for (c)]Use the "E" notation to enter your answer in scientific notation. For example, to enter \( 3.14 \times 10^{-12} \), enter "3.14E-12".**Question Help:** [Message instructor][Submit Question]**Explanation of Diagram:**The diagram is an annular cross-section (a hollow ring) of a cylindrical conductor. The inner circle represents the inner radius \( r_1 = 2.5 \, \text{cm} \) and the outer circle represents the outer radius \( r_2 = 6 \, \text{cm} \). The gray shaded area represents the conducting material. There is an arrow pointing inward, indicating the direction of the current flow into the page, with a uniformly distributed current of 57 A.---

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