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The figure below shows a force versus position graph for a spring/block system.  If Fs=160N and the block is released at x = 12 cm (not shown on figure) how much work is done on the block by the spring as the block goes from x = + 8.0 cm to x = + 5.0 cm.  HInt:  Determine k from the graph.  Don't forget to convert from cm.

The figure below shows a force versus position graph for a spring/block system.  If Fs=160N and the block is released at x = 12 cm (not shown on figure) how much work is done on the block by the spring as the block goes from x = + 8.0 cm to x = + 5.0 cm.  HInt:  Determine k from the graph.  Don't forget to convert from cm.

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The figure below shows a force versus position graph for a spring/block system.  If Fs=160N and the block is released at x = 12 cm (not shown on figure) how much work is done on the block by the spring as the block goes from x = + 8.0 cm to x = + 5.0 cm.  HInt:  Determine k from the graph.  Don't forget to convert from cm.

F, -x (cm) -1 이 F.
Transcribed Image Text:F, -x (cm) -1 이 F.
Expert Solution
Step 1

Solution:

 

From the given graph:

 

The slope of the graph between restoring force and displacement gives spring constant k as:

 

k=160-0-2-0=80 N.cm-1

 

 

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