1. Calculate the work done from x = 0 to x = 7 m by the one-dimensional force depicted in the following graph. Suppose that F = 68 N, calculate the total work by the force over 7 m. Fo HA+A= 3 12 4 6 5 7 -Fo W= √ x (m)

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**Problem Statement:**

1. Calculate the work done from \( x = 0 \) to \( x = 7 \, \text{m} \) by the one-dimensional force depicted in the following graph.

   Suppose that \( F_0 = 68 \, \text{N} \). Calculate the total work by the force over 7 m.

**Diagram Explanation:**

- The graph is a line graph plotting force (\( F \)) against distance (\( x \)).
- The vertical axis represents force in Newtons (N), ranging from \( F_0 \) to \(-F_0\).
- The horizontal axis represents distance in meters (m), from \( x = 0 \) to \( x = 7 \).
- The graph consists of triangular and trapezoidal sections.
  
  Specifically:
  - From \( x = 0 \) to \( x = 1 \), force increases linearly to \( F_0 \).
  - From \( x = 1 \) to \( x = 2 \), force decreases linearly back to zero.
  - From \( x = 2 \) to \( x = 4 \), force decreases linearly to \(-F_0\).
  - From \( x = 4 \) to \( x = 5 \), force increases linearly back to zero.
  - From \( x = 5 \) to \( x = 6 \), force increases linearly to \( F_0 \).
  - From \( x = 6 \) to \( x = 7 \), force decreases linearly back to zero.

**Calculation:**

- Calculate the work done in each section by finding the area under the curve and summing them.
- For triangles, use the formula: \(\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}\).
- For trapezoids, use the formula: \(\text{Area} = \frac{1}{2} \times (\text{base}_1 + \text{base}_2) \times \text{height}\).

**Total Work \( W \)** is computed by summing these areas (considering positive and negative areas where force is above and below the x-axis respectively).

Note: Input the calculated total into the provided text field and express your answer in Joules (J
Transcribed Image Text:**Problem Statement:** 1. Calculate the work done from \( x = 0 \) to \( x = 7 \, \text{m} \) by the one-dimensional force depicted in the following graph. Suppose that \( F_0 = 68 \, \text{N} \). Calculate the total work by the force over 7 m. **Diagram Explanation:** - The graph is a line graph plotting force (\( F \)) against distance (\( x \)). - The vertical axis represents force in Newtons (N), ranging from \( F_0 \) to \(-F_0\). - The horizontal axis represents distance in meters (m), from \( x = 0 \) to \( x = 7 \). - The graph consists of triangular and trapezoidal sections. Specifically: - From \( x = 0 \) to \( x = 1 \), force increases linearly to \( F_0 \). - From \( x = 1 \) to \( x = 2 \), force decreases linearly back to zero. - From \( x = 2 \) to \( x = 4 \), force decreases linearly to \(-F_0\). - From \( x = 4 \) to \( x = 5 \), force increases linearly back to zero. - From \( x = 5 \) to \( x = 6 \), force increases linearly to \( F_0 \). - From \( x = 6 \) to \( x = 7 \), force decreases linearly back to zero. **Calculation:** - Calculate the work done in each section by finding the area under the curve and summing them. - For triangles, use the formula: \(\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}\). - For trapezoids, use the formula: \(\text{Area} = \frac{1}{2} \times (\text{base}_1 + \text{base}_2) \times \text{height}\). **Total Work \( W \)** is computed by summing these areas (considering positive and negative areas where force is above and below the x-axis respectively). Note: Input the calculated total into the provided text field and express your answer in Joules (J
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