1. Calculate the work done from x = 0 to x = 7 m by the one-dimensional force depicted in the following graph. Suppose that F = 68 N, calculate the total work by the force over 7 m. Fo HA+A= 3 12 4 6 5 7 -Fo W= √ x (m)
1. Calculate the work done from x = 0 to x = 7 m by the one-dimensional force depicted in the following graph. Suppose that F = 68 N, calculate the total work by the force over 7 m. Fo HA+A= 3 12 4 6 5 7 -Fo W= √ x (m)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:**Problem Statement:**
1. Calculate the work done from \( x = 0 \) to \( x = 7 \, \text{m} \) by the one-dimensional force depicted in the following graph.
Suppose that \( F_0 = 68 \, \text{N} \). Calculate the total work by the force over 7 m.
**Diagram Explanation:**
- The graph is a line graph plotting force (\( F \)) against distance (\( x \)).
- The vertical axis represents force in Newtons (N), ranging from \( F_0 \) to \(-F_0\).
- The horizontal axis represents distance in meters (m), from \( x = 0 \) to \( x = 7 \).
- The graph consists of triangular and trapezoidal sections.
Specifically:
- From \( x = 0 \) to \( x = 1 \), force increases linearly to \( F_0 \).
- From \( x = 1 \) to \( x = 2 \), force decreases linearly back to zero.
- From \( x = 2 \) to \( x = 4 \), force decreases linearly to \(-F_0\).
- From \( x = 4 \) to \( x = 5 \), force increases linearly back to zero.
- From \( x = 5 \) to \( x = 6 \), force increases linearly to \( F_0 \).
- From \( x = 6 \) to \( x = 7 \), force decreases linearly back to zero.
**Calculation:**
- Calculate the work done in each section by finding the area under the curve and summing them.
- For triangles, use the formula: \(\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}\).
- For trapezoids, use the formula: \(\text{Area} = \frac{1}{2} \times (\text{base}_1 + \text{base}_2) \times \text{height}\).
**Total Work \( W \)** is computed by summing these areas (considering positive and negative areas where force is above and below the x-axis respectively).
Note: Input the calculated total into the provided text field and express your answer in Joules (J
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