The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle. Constant pressure heat addition 3 PV = constant Heat IN Adiabatic expansion 5 Heat OUT (Constant volume heat rejection) Constant volume heat addition 1 Adiabatic. compression Volume (V) Using the Dual Air Standard Cycle and the following data: • Assume constant properties of air. R= 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK; y = 1.4 • Cycle compression ratio = 11 (v1/v2) Air conditions prior to compression: Pressure = 1.6 bar; Temperature = 298K Heat added at constant volume = 290000 J/kg Heat added at constant pressure = 579000 J/kg Pressure (P)

The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle. Constant pressure heat addition 3 PV = constant Heat IN Adiabatic expansion 5 Heat OUT (Constant volume heat rejection) Constant volume heat addition 1 Adiabatic. compression Volume (V) Using the Dual Air Standard Cycle and the following data: • Assume constant properties of air. R= 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK; y = 1.4 • Cycle compression ratio = 11 (v1/v2) Air conditions prior to compression: Pressure = 1.6 bar; Temperature = 298K Heat added at constant volume = 290000 J/kg Heat added at constant pressure = 579000 J/kg Pressure (P)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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IC engines

The term "engine" indicates a mechanical device/machine used to convert input energy to a specific mechanical output. The input energy may be in the form of chemical energy, thermal energy, or so on and mechanical output is in the form of mechanical energy (work done). Generally, the engines classify into two groups which are internal combustion type and external combustion type, and further, these two types can be classified into two types that are reciprocating and rotary engines.

Question

The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle.
Constant pressure
heat addition
3
4
PV = constant
Нeat
IN
Adiabatic
expansion
Heat OUT
(Constant volume
heat rejection)
Constant
volume heat
addition
1
Adiabatic
compression
Volume (V)
Using the Dual Air Standard Cycle and the following data:
• Assume constant properties of air. R= 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK; y = 1.4
Cycle compression ratio = 11 (v1/v2)
Air conditions prior to compression: Pressure = 1.6 bar; Temperature = 298K
Heat added at constant volume = 290000 J/kg
%3D
Heat added at constant pressure = 579000 J/kg
Pressure (P)
2]

g)
Calculate the pressure at point 5.
P5 =
bar
h)
Calculate the cycle efficiency as a percentage.
%

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