The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle. Constant pressure heat addition 3 PV = constant Heat IN Adiabatic expansion 5 Heat OUT (Constant volume heat rejection) Constant volume heat addition 1 Adiabatic. compression Volume (V) Using the Dual Air Standard Cycle and the following data: • Assume constant properties of air. R= 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK; y = 1.4 • Cycle compression ratio = 11 (v1/v2) Air conditions prior to compression: Pressure = 1.6 bar; Temperature = 298K Heat added at constant volume = 290000 J/kg Heat added at constant pressure = 579000 J/kg Pressure (P)

The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle. Constant pressure heat addition 3 PV = constant Heat IN Adiabatic expansion 5 Heat OUT (Constant volume heat rejection) Constant volume heat addition 1 Adiabatic. compression Volume (V) Using the Dual Air Standard Cycle and the following data: • Assume constant properties of air. R= 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK; y = 1.4 • Cycle compression ratio = 11 (v1/v2) Air conditions prior to compression: Pressure = 1.6 bar; Temperature = 298K Heat added at constant volume = 290000 J/kg Heat added at constant pressure = 579000 J/kg Pressure (P)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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