5. This problem involves analysis of selected parts of the ideal Otto cycle. The diagram attached below shows the steps in the cycle. There is a fixed mass of gas in the cylinder which is an ideal gas with constant specific heat values. Parameters relevant to the analysis are: Mass of Gas in the cylinder: m = 0.002 kg Constant Pressure Specific Heat: C, = 1004 J/kg · K Constant Volume Specific Heat: C, = 717 J/kg · K Ratio of Specific Heats: k = Cp/Cy Volume compression Ratio: r, = 10 State 1 Temperature: T = 300 K State 1 Pressure: P = 100 kPa State 3 Temperature: T3 = 2000 K Find the following quantities: a. Temperature at the end of the compression stroke: T, =, Kelvin b. The heat addition (from fuel): Qin = Joules c. The cycle efficiency: 7 = Wnet , and the net work done per cycle: Joules

Elements Of Electromagnetics
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5. This problem involves analysis of selected parts of the ideal Otto cycle. The diagram
attached below shows the steps in the cycle. There is a fixed mass of gas in the cylinder
which is an ideal gas with constant specific heat values. Parameters relevant to the analysis
are:
Mass of Gas in the cylinder: m = 0.002 kg
Constant Pressure Specific Heat: C, = 1004 J/kg · K
Constant Volume Specific Heat: C, = 717 J/kg · K
Ratio of Specific Heats: k = Cp/Cy
Volume compression Ratio: r, = 10
State 1 Temperature: T = 300 K
State 1 Pressure: P = 100 kPa
State 3 Temperature: T3 = 2000 K
Find the following quantities:
a. Temperature at the end of the compression stroke: T, =,
Kelvin
b. The heat addition (from fuel): Qin =
Joules
c. The cycle efficiency: 7 =
Wnet
, and the net work done per cycle:
Joules
Transcribed Image Text:5. This problem involves analysis of selected parts of the ideal Otto cycle. The diagram attached below shows the steps in the cycle. There is a fixed mass of gas in the cylinder which is an ideal gas with constant specific heat values. Parameters relevant to the analysis are: Mass of Gas in the cylinder: m = 0.002 kg Constant Pressure Specific Heat: C, = 1004 J/kg · K Constant Volume Specific Heat: C, = 717 J/kg · K Ratio of Specific Heats: k = Cp/Cy Volume compression Ratio: r, = 10 State 1 Temperature: T = 300 K State 1 Pressure: P = 100 kPa State 3 Temperature: T3 = 2000 K Find the following quantities: a. Temperature at the end of the compression stroke: T, =, Kelvin b. The heat addition (from fuel): Qin = Joules c. The cycle efficiency: 7 = Wnet , and the net work done per cycle: Joules
3,
echteadher.com
V½-V3
V=V4 v
2.
Transcribed Image Text:3, echteadher.com V½-V3 V=V4 v 2.
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